In figure PA and PB are tangents from P to the circle with centre O. R is a point on the circle. Prove that : PC + CR = PD + DR
Since tangent to a circle is perpendicular to the radius throgh the point of contact.
⇒ ∠OTP = 90°
In right ΔOTP, we have
OP2 = OT2 + PT2
⇒ (13)2 = OT2 + (12)2
OT2 = 169 – 144 = 25
⇒ OT = 5
Hence, the radius of the circle is 5 cm.