If one root of the equation x2 + (1 - 3i)x - 2(1 + i) = 0 is - 1

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 Multiple Choice QuestionsMultiple Choice Questions

181.

If a, b, c are real, then both the roots of the equation (x - b)(x - c) + (x - c)(x - a) + (x - a)(x - b) = 0

  • positive

  • negative

  • real

  • imaginary


182.

The modulus of 1 - i3 + i + 4i5 is

  • 5 unit

  • 115 unit

  • 55 unit

  • 125


183.

If α, β be the roots of x2 - a(x - 1) + b = 0, then the value of 1α2 -  + 1β2 -  + 2a +b is

  • 4a + b

  • 1a + b

  • 0

  • - 1


184.

The sum of all real roots of the equation x - 22 + x - 2 - 2 = 0 is

  • 7

  • 4

  • 1

  • 5


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185.

The quadratic equation whose roots are three times the roots of 3ax2 + 3bx + c = 0 is

  • ax2 + 3bx + 3c = 0

  • ax2 + 3bx + c

  • 9ax2 + 9bx + c

  • ax2 + bx + 3c


 Multiple Choice QuestionsShort Answer Type

186.

Find the values of 'a' for which the expression x2 - (3a - 1)x + 2a2 + 2a - 11 is always positive


 Multiple Choice QuestionsMultiple Choice Questions

187.

The value of (1 - w + w2)5 + (1 + w - w2)5, where w and w2 are the complex cube roots of unity, is

  • 0

  • 32w

  • - 32

  • 32


188.

Let α, β be the roots of x2 - 2xcosϕ + 1 = 0, then the equation whose roots are αn, βn is

  • x2 - 2xcos - 1 = 0

  • x2 - 2xcos + 1 = 0

  • x2 - 2xsin + 1 = 0

  • x2 + 2xsin - 1 = 0


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189.

If one root of the equation x2 + (1 - 3i)x - 2(1 + i) = 0 is - 1 + i, then the other root is

  • - 1 - i

  • - 1 - i2

  • i

  • 2i


D.

2i

Let another root of the equation,

x2 + (1 - 3i)x - 2(1 + i) = 0 is α

 α + (- 1 + i) = - (1 - 3i)                     α = - 1 +3i + 1 - i                            = 2i


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190.

The equation x2 - 3x + 2 = 0 has

  • no real root

  • one real root

  • two real root

  • four real root


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