Draw a line segment of length 8 cm and divide it internally in the ratio 4: 5.
Steps of construction.
Construct an isosceles triangle with base 8 cm and altitude 4 cm. Construct another triangle whose sides are 2/3 times the corresponding sides of the isosceles triangle.
Draw a triangle ABC with BC = 6 cm, AB = 5 cm and ∠ABC 60. Then construct a triangle whose sides are 3/4 of the corresponding sides of the △ABC.
Construct a tangent of a circle of radius 4 cm from a point on the concentriccircle of radius 6 cm.
Draw a line segment AB of length 8 cm. Taking A as centre, draw a circle of radius 4 cm and taking B as centre, draw another circle of radius 3 cm. Construct tangents to each circle from the centre of the other circle.
Construct a triangle ABC with side BC = 7 cm, ∠B = 45°, ∠A = 105°. Then construct another triangle whose sides are 3/4 times the corresponding sides of the Δ ABC.
Steps of constructions:
1) Draw BC = 7 cm.
<2)
At B, construct ∠CBX = 45° and at C, construct
∠BCY = 180 - (45 + 105) = 30°
3) Let BX and CY intersect at A, &DElta; ABC so obtained is the given triangle.
4) Construct an acute angle Δ CBZ at B on opposite side of vertex A of δ ABC.
5) Mark-off four points ( greater of 4 and 3 in 3/4 points B1, B2, B3,B4 on BZ such that BB1 = B1B2 = B2B3 = B3B4.
6) Join B4 to C.
7) Draw B3C' parallel to B4C which meets BC at C'.
8) From C', draw C'A' parallel to CA meeting at A'.
Thus, A'BC' is the required triangle, each of whose side is times
the corresponding sides of
Draw a triangle ABC with side BC = 6 cm, C = 300 and A = 1050. Then construct another triangle whose sides are times the corresponding sides of ABC.