Find the value of k so that the function f is continuous at the

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 Multiple Choice QuestionsShort Answer Type

91. Discuss the continuity of the function f given by
straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell 2 plus straight x space comma space if space straight x not equal to 0 end cell row cell space space space space space 2 space space comma space if space straight x equals 0 end cell end table close
at space straight x equals 0
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92. Discuss the continuity of the function

straight f left parenthesis straight x right parenthesis equals open curly brackets table row cell space space space space space space space straight x space space comma space 0 less or equal than straight x less than 1 half end cell row cell straight x over 2 space comma space straight x equals 1 half end cell row cell space 1 minus straight x space space comma space 1 half less than straight x less or equal than 1 end cell end table close
at space straight x equals 1 half
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93. Discuss the continuity of the functions

straight f left parenthesis straight x right parenthesis equals open curly brackets table row cell space space space space space space straight x space space comma space space space straight x greater than 0 end cell row cell space space space space space 1 space space space comma space space space straight x equals 0 end cell row cell space minus straight x space space space comma space space space straight x less than 0 end cell end table close
at space straight x equals 0
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94. Discuss the continuity of the function

straight f left parenthesis straight x right parenthesis equals open curly brackets table row cell 1 half minus straight x space space comma space 0 less or equal than straight x less than 1 half end cell row cell 1 space space space space space space comma space straight x equals 1 half end cell row cell 3 over 2 minus straight x space space comma 1 half less than straight x less or equal than 1 end cell end table close
at space straight x equals 1 half
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95.

Let
straight f left parenthesis straight x right parenthesis equals open curly brackets table row cell 1 minus straight x space space space comma space space 0 less or equal than straight x less than 1 half end cell row cell 0 space space space comma space space straight x equals 1 half end cell row cell space space space straight x space space space space space space comma space space 1 half less than straight x less than 1 end cell end table close
Discuss continuity of f(x) at space straight x equals 1 half

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96. Find the relationship between a and b so that the function f defined by
straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell straight a space straight x plus 1 comma space space space if space straight x less or equal than 3 end cell row cell straight b space straight x plus 3 comma space space space if space straight x greater than 3 end cell end table close
is continous at x=3
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97. For what value of λ is the function defined by
straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell straight lambda open parentheses straight x squared minus 2 straight x close parentheses comma space if space straight x less or equal than 0 end cell row cell 4 straight x plus 1 comma space space space space space space space if space straight x greater than 0 end cell end table close
continous at x=0? What about continuity at x=1?
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98.

In the following , find the value of the constant k so that the given function is continuous at the indicated point:
straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell straight k space straight x plus 5 space space comma space if space straight x less or equal than 2 end cell row cell straight x minus 1 space space space space space comma space if space straight x greater than 2 end cell end table close
at space straight x equals 2.

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99. Find the value of k so that the function f is continuous at the indicated point
straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell straight k space straight x plus 1 comma space if space straight x less or equal than straight pi end cell row cell cos space straight x space space comma space if space straight x greater than straight pi end cell end table close
at space straight x equals straight pi


Here space straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell straight k space straight x plus 1 comma space if space straight x less or equal than straight pi end cell row cell cos space straight x space space comma space if space straight x greater than straight pi end cell end table close
space Lt with straight x rightwards arrow straight pi to the power of minus below straight f left parenthesis straight x right parenthesis equals Lt with straight x rightwards arrow straight pi to the power of minus below left parenthesis kx plus 1 right parenthesis
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space left square bracket Put space straight x equals straight pi minus straight h comma space straight h greater than 0 space so space that space straight h rightwards arrow 0 space as space straight x rightwards arrow straight pi to the power of minus right square bracket
space space space space space space space space space space space space space space space space space equals Lt with straight x rightwards arrow 0 below left curly bracket straight k left parenthesis straight pi minus straight h right parenthesis plus 1 right curly bracket equals straight k left parenthesis straight pi minus 0 right parenthesis equals 1 equals straight k space straight pi plus 1
space Lt with straight x rightwards arrow straight pi to the power of plus below straight f left parenthesis straight x right parenthesis equals Lt with straight x rightwards arrow straight pi to the power of plus below space cos space straight x
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space left square bracket Put space straight x equals straight pi plus straight h comma space straight h greater than 0 space so space that space straight h rightwards arrow 0 space as space straight x rightwards arrow straight pi to the power of plus right square bracket
space space space space space space space space space space space space space space space space space equals Lt with straight h rightwards arrow 0 below cos left parenthesis straight pi plus straight h right parenthesis equals Lt with straight h rightwards arrow 0 below left parenthesis cos space straight pi space cos space straight h minus sin space straight pi space sin space straight h right parenthesis
space space space space space space space space space space space space space space space space space equals cos space straight pi.1 minus sin space straight pi.0 equals cos equals negative 1
Since space straight f space is space continous space at space straight x equals straight pi
therefore space space Lt with straight x rightwards arrow straight pi to the power of minus below straight f left parenthesis straight x right parenthesis equals Lt with straight x rightwards arrow straight pi to the power of plus below straight f left parenthesis straight x right parenthesis
therefore space straight k space ππ equals negative 1 space rightwards double arrow straight k space straight pi equals negative 2 space space rightwards double arrow space straight k equals negative 2 over straight pi
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100. Find the value of k so that the function f is continuous at the indicated point
straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell straight k space straight x squared space comma space straight x greater or equal than 2 end cell row cell space space 3 space space space comma space straight x less than 2 end cell end table close
at space straight x equals 2
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