from Mathematics Continuity and Differentiability

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 Multiple Choice QuestionsShort Answer Type

251. If space straight x to the power of straight y equals straight y to the power of straight x comma space prove space that space dy over dx equals fraction numerator begin display style straight y over straight x end style minus log space straight y over denominator begin display style straight x over straight y end style minus log space straight x end fraction
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252. If space straight y equals straight x to the power of straight y comma space prove space that space dy over dx equals fraction numerator straight y squared over denominator straight x left parenthesis 1 minus straight y space log space straight x right parenthesis end fraction.


Here space space space space space straight y equals straight x to the power of straight y
therefore space log space straight y equals log space straight x to the power of straight y space space space space space space space space space rightwards double arrow space log space straight y equals straight y space log space straight x
Differentiating space both space sides space straight w. straight r. straight t. straight x comma space we space get comma
1 over straight y dy over dx equals straight y.1 over straight x plus log space straight x. dy over dx
therefore space open parentheses 1 over straight y minus log space straight x close parentheses dy over dx equals straight y over straight x space space space space rightwards double arrow space open parentheses fraction numerator 1 minus straight y space log space straight x over denominator straight y end fraction close parentheses dy over dx equals straight y over straight x
therefore space space space space space space space space space space space space space dy over dx equals fraction numerator straight y squared over denominator straight x left parenthesis 1 minus straight y space log space straight x right parenthesis end fraction.
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253. Find space dy over dx when space xy equals straight e to the power of straight x minus straight y end exponent.
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255. If space straight y equals square root of fraction numerator 1 minus straight x over denominator 1 plus straight x end fraction end root comma space prove space that space left parenthesis 1 minus straight x squared right parenthesis dy over dx plus straight y equals 0
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256. If space straight f left parenthesis straight x right parenthesis equals open parentheses fraction numerator 3 plus straight x over denominator 1 plus straight x end fraction close parentheses to the power of 2 plus 3 straight x end exponent comma space find space straight f apostrophe left parenthesis 0 right parenthesis
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257. Differentiate space square root of fraction numerator left parenthesis straight x minus 3 right parenthesis left parenthesis straight x squared plus 4 right parenthesis over denominator 3 straight x squared plus 4 straight x plus 5 end fraction end root straight w. straight r. straight t. straight x
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258. Differentiate space square root of fraction numerator left parenthesis straight x minus 1 right parenthesis left parenthesis straight x minus 2 right parenthesis over denominator left parenthesis straight x minus 3 right parenthesis left parenthesis straight x minus 4 right parenthesis left parenthesis straight x minus 5 right parenthesis end fraction end root straight w. straight r. straight t. straight x
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259. Differentiate : (x + 3)2 (x + 4)3 (x + 5)4.w.r.t.x.
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260.

Find the derivative of the function given by

f(x)=(1 + x)(1 + x2)(1 + x4)(1 + x8)and hence find f'(1).

 
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