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 Multiple Choice QuestionsShort Answer Type

251. If space straight x to the power of straight y equals straight y to the power of straight x comma space prove space that space dy over dx equals fraction numerator begin display style straight y over straight x end style minus log space straight y over denominator begin display style straight x over straight y end style minus log space straight x end fraction
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252. If space straight y equals straight x to the power of straight y comma space prove space that space dy over dx equals fraction numerator straight y squared over denominator straight x left parenthesis 1 minus straight y space log space straight x right parenthesis end fraction.
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253. Find space dy over dx when space xy equals straight e to the power of straight x minus straight y end exponent.
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255. If space straight y equals square root of fraction numerator 1 minus straight x over denominator 1 plus straight x end fraction end root comma space prove space that space left parenthesis 1 minus straight x squared right parenthesis dy over dx plus straight y equals 0
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256. If space straight f left parenthesis straight x right parenthesis equals open parentheses fraction numerator 3 plus straight x over denominator 1 plus straight x end fraction close parentheses to the power of 2 plus 3 straight x end exponent comma space find space straight f apostrophe left parenthesis 0 right parenthesis


space space space space space space space space space space space space space straight f left parenthesis straight x right parenthesis equals open parentheses fraction numerator 3 plus straight x over denominator 1 plus straight x end fraction close parentheses to the power of 2 plus 3 straight x end exponent
therefore space space space log space straight f left parenthesis straight x right parenthesis equals log open parentheses fraction numerator 3 plus straight x over denominator 1 plus straight x end fraction close parentheses to the power of 2 plus 3 straight x end exponent
rightwards double arrow space space log space straight f left parenthesis straight x right parenthesis equals left parenthesis 2 plus 3 straight x right parenthesis open parentheses fraction numerator 3 plus straight x over denominator 1 plus straight x end fraction close parentheses
rightwards double arrow space space log space straight f left parenthesis straight x right parenthesis equals left parenthesis 2 plus 3 straight x right parenthesis left square bracket log left parenthesis 3 plus straight x right parenthesis minus log left parenthesis 1 plus straight x right parenthesis right square bracket
Differentiating space both space sides space straight w. straight r. straight t. straight x comma space we space get comma
fraction numerator 1 over denominator straight f left parenthesis straight x right parenthesis end fraction. straight f apostrophe left parenthesis straight x right parenthesis equals left parenthesis 2 plus 3 straight x right parenthesis. open square brackets fraction numerator 1 over denominator 3 plus straight x end fraction minus fraction numerator 1 over denominator 1 plus straight x end fraction close square brackets plus 3. left square bracket log left parenthesis 3 plus straight x right parenthesis minus lg left parenthesis 1 plus straight x right parenthesis right square bracket
Put space straight x equals 0
therefore space 1 over 9 straight f apostrophe left parenthesis 0 right parenthesis equals left parenthesis 2 plus 0 right parenthesis. open square brackets fraction numerator 1 over denominator 3 plus 0 end fraction minus fraction numerator 1 over denominator 1 plus 0 end fraction close square brackets plus 3. left square bracket log left parenthesis 3 plus 0 right parenthesis minus lg left parenthesis 1 plus 0 right parenthesis right square bracket
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space open square brackets because space straight f left parenthesis 0 right parenthesis equals open parentheses fraction numerator 3 plus 0 over denominator 1 plus 0 end fraction close parentheses to the power of 2 plus 0 end exponent equals 3 squared equals 9 close square brackets
rightwards double arrow space 1 over 9 straight f apostrophe left parenthesis 0 right parenthesis equals 2 open parentheses fraction numerator 1 minus 3 over denominator 3 end fraction close parentheses plus 3 left parenthesis log space 3 minus 0 right parenthesis
rightwards double arrow space straight f apostrophe left parenthesis 0 right parenthesis equals negative 12 plus 27 space log space 3.
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257. Differentiate space square root of fraction numerator left parenthesis straight x minus 3 right parenthesis left parenthesis straight x squared plus 4 right parenthesis over denominator 3 straight x squared plus 4 straight x plus 5 end fraction end root straight w. straight r. straight t. straight x
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258. Differentiate space square root of fraction numerator left parenthesis straight x minus 1 right parenthesis left parenthesis straight x minus 2 right parenthesis over denominator left parenthesis straight x minus 3 right parenthesis left parenthesis straight x minus 4 right parenthesis left parenthesis straight x minus 5 right parenthesis end fraction end root straight w. straight r. straight t. straight x
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259. Differentiate : (x + 3)2 (x + 4)3 (x + 5)4.w.r.t.x.
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260.

Find the derivative of the function given by

f(x)=(1 + x)(1 + x2)(1 + x4)(1 + x8)and hence find f'(1).

 
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