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 Multiple Choice QuestionsShort Answer Type

551. If y=ea xsin bx, prove thatfraction numerator straight d squared straight y over denominator dx squared end fraction minus 2 straight a dy over dx plus left parenthesis straight a squared plus straight b squared right parenthesis straight y equals 0
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552. If space straight y equals straight x space log open parentheses fraction numerator straight x over denominator straight a plus straight b space straight x end fraction close parentheses comma space prove space that space straight x cubed fraction numerator straight d squared straight y over denominator dx squared end fraction equals open parentheses straight x dy over dx minus straight y squared close parentheses.
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553. If space straight x equals tan open parentheses 1 over straight a log space straight y close parentheses comma space show space that space left parenthesis 1 plus straight x squared right parenthesis fraction numerator straight d squared straight y over denominator dx squared end fraction plus left parenthesis 2 space straight x minus straight a right parenthesis dy over dx equals 0.


Here space space space straight x equals tan open parentheses 1 over straight a log space straight y close parentheses
therefore space tan to the power of negative 1 end exponent straight x equals 1 over straight a log space straight y space space or space space log space straight y equals straight a space tan to the power of negative 1 end exponent straight x
Differentiating space straight w. straight r. straight t. straight x comma space we space get comma
space space space space space space space space space space fraction numerator 1 over denominator space straight y end fraction dy over dx equals fraction numerator straight a over denominator 1 plus straight x squared end fraction
or space space space left parenthesis 1 plus straight x squared right parenthesis dy over dx equals straight a space straight y
Again space differentiating space straight w. straight r. straight t. straight x comma space we space get comma
space space space space space space space left parenthesis 1 plus straight x squared right parenthesis fraction numerator straight d squared straight y over denominator dx squared end fraction plus dy over dx space 2 space straight x equals straight a dy over dx
therefore space space space left parenthesis 1 plus straight x squared right parenthesis fraction numerator straight d squared straight y over denominator dx squared end fraction plus left parenthesis 2 space straight x minus straight a right parenthesis dy over dx equals 0.
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554. If y=xx, prove that fraction numerator straight d squared straight y over denominator dx squared end fraction minus 1 over straight y open parentheses dy over dx close parentheses squared minus straight y over straight x equals 0.
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555. If space space space space straight y equals left parenthesis straight a plus straight b space straight t right parenthesis space straight e to the power of straight n space straight t end exponent comma space prove space that space fraction numerator straight d squared straight y over denominator dx squared end fraction minus 2 straight n dy over dx plus straight n squared straight y equals 0.
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556. If space straight y equals fraction numerator straight a space straight x plus straight b over denominator straight c space straight x plus straight d end fraction comma space prove space that space 2 straight y subscript 1 space straight y subscript 3 equals 3 space straight y subscript 2 squared.
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557. If space straight y equals log space left parenthesis 1 plus cos space straight x right parenthesis comma space prove space that space straight y subscript 1 space straight y subscript 2 plus straight y subscript 3 equals 0.
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558. If space 2 space straight y equals straight x open parentheses 1 plus dy over dx close parentheses comma space show space that space fraction numerator straight d squared straight y over denominator dx squared end fraction space is space constant space.
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559. If y = (tan-1 x)2, then prove that (1 + x2)2 y2 + 2x(1 + x2)y1 = 2.
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560. If space straight y equals sin to the power of negative 1 end exponent straight x comma space then space show space that space open parentheses 1 minus straight x squared close parentheses fraction numerator straight d squared straight y over denominator dx squared end fraction minus straight x dy over dx equals 0.
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