Show that the function is continuous but not differentiable at x=3.
Determine the value of the constant ‘k’ so that the function is continuous at x = 0.
For what value of k is the following function continuous at x = 2?
f ( x ) =2x + 1 ; x<2 k ; x = 2 3x - 1 ; x>1
The given function f(x) will be continuous at x = 2, if
limx→2-f(x) = limx→2+f(x) = f(2)limx→2-f(x) = limx→2- 2x + 1 = 2 x 2 + 1 = 5limx→2+f(x) = limx→2+ 3x - 1 = 3 x 2 - 1 = 5∴ f(2) = k⇒ k = 5
Thus, for k = 5, the given function is continuous at x = 2.
Differentiate the following function w.r.t. x:
y = sinxx + sin-1x
Find dydx if (x2 + y2)2 = xy.
If y =3 cos ( log x ) + 4 sin ( log x ), then show that x2 d2ydx2 + x dydx + y = 0