If Then, the value of the pair (a, b) for which f(x) cannot be continuous at x = 1, is
(2, 0)
(1, - 1)
(4, 2)
(1, 1)
Which of the following function is not differentiable at x = 1 ?
f(x) =
f(x) =
f(x) =
None of the above
Using Rolle's theorem, the equation a0xn + a1xn - 1 + ... + an = 0 has atleast one root between 0 and 1, if
na0 + (n - 1)a1 + ... + an - 1 = 0
The value of cfrom the Lagrange's mean value theorem for which f(x) = in [1, 5], is
5
1
None of these
C.
It is clear that f(x) has a definite and unique value for each x [1, 5].
Thus, for every point in the interval [1, 5], the value of f(x) exists.
So, f(x) is continuous in the interval [1, 5].
Also, f'(x) = , hich clearly exists for all x in an open interval (1,5).
Hence, f'(x) is differentiable in (1, 5).
So, there must be a value c [1, 5] such that
Let f'(x), be differentiable a. If f(1) = - 2 and f'(x) 2 x [1, 6], then
f(6) < 8
f(6) 8
f(6) 5
f(6) 5