The number of points at which the function is discontinuous, is
1
2
3
infinitely many
C.
3
At x = 0, ± 1, the function is discontinuous.
At x = 0, loge[x] is not defined.
At x = 1 and - 1, loge[x] is 0, hence
f(x) =
So, x = 0, ± 1 are the points of discontinuity.
Thus, there are three ponts of discontinuity.
The functions f, g and h satisfy the relations f'(x) = g (x + 1) and g'(x) = h(x - 1). Then, f"(2x) is equal to
h(2x)
4h(2x)
h(2x - 1)
h(2x + 1)
If y = f(x) is continuous on [0, 6], differentiable on (0, 6), f(0) = - 2 and f(6) = 16, then at some point between x = 0 and x = 6, f'(x) must be equal to
- 18
- 3
3
14
Let f(x + y) = f(x) f(y) and f(x) = 1 + sin(3x) g(x), where g is differentiable.The f'(x) is equal to
3f(x)
g(0)
f(x)g(0)
3g(x)