The functions f, g and h satisfy the relations f'(x) = g (x + 1) and g'(x) = h(x - 1). Then, f"(2x) is equal to
h(2x)
4h(2x)
h(2x - 1)
h(2x + 1)
If y = f(x) is continuous on [0, 6], differentiable on (0, 6), f(0) = - 2 and f(6) = 16, then at some point between x = 0 and x = 6, f'(x) must be equal to
- 18
- 3
3
14
If f(x) = , then f'(2) is equal to
0
- 1
1
2
A.
0
We have,
Let f(x + y) = f(x) f(y) and f(x) = 1 + sin(3x) g(x), where g is differentiable.The f'(x) is equal to
3f(x)
g(0)
f(x)g(0)
3g(x)