ddxseccos-1x8 is equal to from Mathematics Continuity and D

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 Multiple Choice QuestionsMultiple Choice Questions

801.

Let f R  R : be differentiable at c  R  and f(c) = 0. If g(x) = fx, then at x = c , g is

  • not differentiable

  • differentiable if f'(c) = 0

  • not differentiable if f'(c) = 0

  • differentiable if f'(c)  0


802.

If f(x) is continuous on - π, π, where

fx = - 2sinx,      for - π  x  - π2αsinx + β,   for - π2 < x < π2cosx,            for π2  x  π

then α and β are

  • - 1, - 1

  • 1, - 1

  • 1, 1

  • - 1, 1


803.

If f(x) = log1 - 3x1 +3x,      for x  0k,                                for x = 0 continuous at x = 0, then k is equal to

  • - 2

  • 2

  • 1

  • - 1


804.

If x = log1 + t2 and y = t - tan-1t. Then, dydx is equal to

  • ex - 1

  • t2 - 1

  • ex - 12

  • ex - y


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805.

ddxseccos-1x8 is equal to

  • 18

  • - 18

  • 8x2

  • 8x2


D.

8x2

We know that, sec-1x = cos-11xddxseccos-1x8= ddxsecsec-18x8x2= - 8x2


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806.

If f(x) = 1 + cos2x2, then f'π2 is

  • π6

  • - π6

  • 16

  • π6


807.

If y = asin3θ and x = acos3θ, then at θ = π3, dydx is equal to

  • π6

  • - 3

  • - 13

  • 3


808.

2y0 is equal to

  • 2y2 - 2y1 - y0

  • y2 - 2y1 - y0

  • 2y2 - 2y1 + y0

  • y2 - 2y1 + y0


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809.

23ex is equal to

  • 3ex

  • 3(h - 1)ex

  • 3(eh - 1)2ex

  • None of the above


810.

The value of 2Ex2 at the interval h = 1 is

  • 0

  • 1

  • 2

  • 4


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