If y = log(log(x)), then d2ydx2 is equal to from Mathe

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 Multiple Choice QuestionsMultiple Choice Questions

931.

The function f(x) = [x], where [x] denotes greatest integer function, is continuous at

  • 1

  • 4

  • 1.5

  • - 2


932.

If y = log1 - x21 + x2, then dydx is equal to

  • 11 - x4

  • - 4x1 - x4

  • - 4x31 - x4

  • 4x31 - x4


933.

The two curves x3 - 3xy2 + 2 = 0 and 3x2y - y3 = 2

  • cut at angle π/3

  • touch each other

  • cut at angle π4

  • cut at right angle


934.

If y = esin-1t2 - 1 and x = esec-11t2 - 1, then dydx is equal to

  • xy

  • - yx

  • yx

  • - xy


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935.

If xy = ex - y, then dydx is equal to

  • logxlogx - y

  • exxx - y

  • logx1 + logx2

  • 1y - 1x - y


936.

The function f(x) = [x], where [x] is the greatest integer function, is continuous at

  • 1.5

  • 4

  • 1

  • - 2


937.

If tan-1x2 + y2 = α, then dydx is equal to

  • - xy

  • xy

  • xy

  • - xy


938.

If y = fxgxhxlmnabc, then dydx is equal to

  • f'xg'xh'xlmnabc

  • lmnfxgxhxabc

  • f'xlag'xmbh'xnc

  • lmnabcf'xg'xh'x


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939.

If f(x) = kx2 if x  23    if x > 2is continuous at x = 2, then the value of k is

  • 3/4

  • 4

  • 4/3

  • 3


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940.

If y = log(log(x)), then d2ydx2 is equal to

  • - 1 + logxx2logx

  • - 1 + logxxlogx2

  • 1 + logxxlogx2

  • 1 + logxx2logx


B.

- 1 + logxxlogx2

We have, y = loglogx dydx = 1logx 1x           = 1xlogx           = xlogx- 1Again differentiating w.r.t. x, we getd2ydx2 = - xlogx- 1 - 11 . logx + x . 1x        = - xlogx- 2logx + 1        = - 1 + logxxlogx2


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