If: R → R is defined by f (x) = x - [x], wher

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 Multiple Choice QuestionsMultiple Choice Questions

1001.

One root of the equation x2 - 4x+ 1 = 0 is between 1 and 2. The value ofthis root using Newton-Raphson method will be

  • 1.775

  • 1.850

  • 1.875

  • 1.950


1002.

The point/points of discontinuity of the function f(x) = x + 3,     if x  - 3- 2x,         if - 3 < x < 36x + 2,      if x  3 is/are

  • 3, - 3

  • 3

  • - 3

  • None of these


1003.

The value of ddxsintan-1ex at x = 0  is

  • 0

  • - 2

  • - 122

  • - 12


1004.

If f(x) = x2 - 10x + 25x2 - 7x + 10 and f is continuous at x = 5, then f(5) is equal to

  • 0

  • 5

  • 10

  • 25


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1005.

If h(x) = xxx, then at x = 1, h'xhx is equal to

  • h(x)

  • 1hx

  • 1 + loghx

  • - loghx


1006.

ddxsin-13x - 4x3 is equal to

  • 34 - x2

  • 31 - x2

  • 14 - x2

  • - 14 - x2


1007.

If f(x) = x2x + a, then f''(a) is equal to

  • 4a

  • 18a

  • 14a

  • 8a


1008.

If u = ex2 - y2, then

  • xux = yuy

  • yux = xyy

  • yux + xuy = 0

  • x2uy + y2ux = 0


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1009.

If u = xy2tan-1yx, then xux + yuy is equal to

  • 2u

  • u

  • 3u

  • 13u


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1010.

If: R  R is defined by f (x) = x - [x], where[x] is the greatest integer not exceeding x, then the set of discontinuous of f is

  • the empty set

  • R

  • Z

  • N


C.

Z

We know that,

  fx = x - n - 1    for - 1 < x < n        = 0                     for x = n        = x - n              for n < x < n + 1where n  zNow, we check the continuity at x = n               fn - 0 = limxn- x - n - 1                             =limh0 n - h - n + 1                             = 1              fn + 0 =limxn+ x - n                              = limh0 n + h - n = 0and               fn  =  0fx is discontinuous at x = n Set of discontinuous of f is z


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