Find the area of a rhombus if its vertices are (3, 0), (4, 5), (

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 Multiple Choice QuestionsShort Answer Type

131.

Find the coordinates of a point A, where AB is the diameter of a circle whose centre is (2, – 3) and B is (1, 4).

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132.

If A and B are (– 2, – 2) and (2, – 4), respectively, find the coordinates of P such that  

AP space equals space 3 over 7 and P lies on the line segment Ab.

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 Multiple Choice QuestionsLong Answer Type

133.

Find the coordinates of the points which divide the line segment joining A(– 2, 2) and B(2, 8) into four equal parts.

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134.

Find the area of a rhombus if its vertices are (3, 0), (4, 5), (– 1, 4) and (– 2, – 1) taken in order.


Let the given points are A(3, 0), B(4, 5), C(-1, 4) and D(-2, -1).


Let the given points are A(3, 0), B(4, 5), C(-1, 4) and D(-2, -1).Now


BD space equals space square root of left parenthesis negative 2 minus 4 right parenthesis squared plus left parenthesis negative 1 minus 5 right parenthesis squared end root
space space space space space space equals space square root of left parenthesis negative 6 right parenthesis squared plus left parenthesis negative 6 right parenthesis squared end root equals square root of 36 plus 36 end root equals square root of 72
space space space space space space equals space 6 square root of 2 space units
AC space equals space square root of left parenthesis negative 1 minus 3 right parenthesis squared plus left parenthesis 4 minus 0 right parenthesis squared end root
space space space space space space equals square root of left parenthesis negative 4 right parenthesis squared plus left parenthesis 4 right parenthesis squared end root equals square root of 16 plus 16 end root equals square root of 32

Now, Area of rhombus ABCD

equals 1 half straight x space left parenthesis Product space of space diagonals right parenthesis
rightwards double arrow space Area space of space rhombus space equals space 1 half straight x space left parenthesis AC space straight x space BD right parenthesis
equals open square brackets 1 half straight x 4 square root of 2 straight x 6 square root of 2 close square brackets space sq. space units
equals left parenthesis 2 square root of 2 straight x 6 square root of 2 right parenthesis space sq. space units space equals space 24 space sq. space units.




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 Multiple Choice QuestionsShort Answer Type

135.

Find the area of the triangle whose vertices are :
(2, 3), (–1, 0), (2, – 4)

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136.

Find the area of the triangle whose vertices are:
(–5, –1), (3, –5), (5, 2)

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In each of the following find the value of ‘k’, for which the points are collinear
(7, –2), (5, 1), (3, k)

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138.

In each of the following find the value of ‘k’, for which the points are collinear
(8, 1), (k, – 4), (2, –5) 

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139.

Find the area of the triangle formed by joining the mid-points of the sides of the triangle whose vertices are (0, –1), (2, 1) and (0, 3). Find the ratio of this area to the area of the given triangle.

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 Multiple Choice QuestionsLong Answer Type

140.

Find the area of the quadrilateral whose vertices, taken in order, are (– 4, – 2), (– 3, – 5), (3, – 2) and (2, 3).

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