The coordinates of the vertices of ∆ABC are A(4, 1), B(-3, 2) and C(0, k). Given that the area of ABC is 12 unit2, find the value of k.
Here, we have x1 = 4 x2 = -3 x3 = 0 y1 = 1 y2 = 2 y3 = k Now, Area of ∆ABC
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172.Find the area of the ∆ABC with vertices A(-5, 7), B(-4, -5), and C(4, 5).
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173.For what value of k are the points (1, 1), (3, k) and (-1, 4) collinear.
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174.For what value of p are the points (2, 1), (p, -1) and (-1, 3) collinear.
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175.Find the area of the rhombus whose vertices taken in order are the points (3, 0), (4, 5), (-1, 4) and (-2, -1).
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176.Find the distance between the points (cos ө - sin ө), (-cos ө, sin ө)
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177.Find the distance between the points Let the given points be A (a cos ө, 0) and B(0, a sin ө)
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178.Find the distance between the points Let the given points be A(0, 0) and B(6, 8) we know that distance between two points A(x1, y1) and B(x2, y2) is given by
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179.Find the co-ordinates of the mid-point of the line segment joining (-5, 4) and (6, -7).
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180.Find the co-ordinates of the mid-point of the line segment joining (4, 7) and (6, 9).
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