The coordinates of the vertices of ∆ABC are A(4, 1), B(-3, 2) and C(0, k). Given that the area of ABC is 12 unit2, find the value of k.
Here, we have
x1 = 3, y1 = 0
x2 = 4, y2 = 5
and x3 = -1, y3 = 4
Now, area of ∆ABD
Here,
Now, area of rhombus (ABCD)
= 2 × ar (∆ABC)
2 × 12 = 24 Sq. units.