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Coordinate Geometry

Short Answer Type

171.

The coordinates of the vertices of ∆ABC are A(4, 1), B(-3, 2) and C(0, k). Given that the area of ABC is 12 unit², find the value of k.

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172. Find the area of the ∆ABC with vertices A(-5, 7), B(-4, -5), and C(4, 5).

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173. For what value of k are the points (1, 1), (3, k) and (-1, 4) collinear.

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174. For what value of p are the points (2, 1), (p, -1) and (-1, 3) collinear.

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175. Find the area of the rhombus whose vertices taken in order are the points (3, 0), (4, 5), (-1, 4) and (-2, -1).

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176. Find the distance between the points
(cos ө - sin ө), (-cos ө, sin ө)

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177. Find the distance between the points
Let the given points be A (a cos ө, 0) and B(0, a sin ө)

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178. Find the distance between the points
Let the given points be A(0, 0) and B(6, 8) we know that distance between two points A(x₁, y₁) and B(x₂, y₂) is given by

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179. Find the co-ordinates of the mid-point of the line segment joining (-5, 4) and (6, -7).

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180. Find the co-ordinates of the mid-point of the line segment joining (4, 7) and (6, 9).

Let the given points be A(4, 7) and B(6, 9).
Here, we have
x₁ = 4, y₁ = 7
x₂ = 6, y₂ = 9
Let the mid-point be P(x, y).

$Then space straight x equals fraction numerator 4 plus 6 over denominator 2 end fraction space and space straight y space equals fraction numerator 7 plus 9 over denominator 2 end fraction rightwards double arrow space space straight x space equals space 5 space and space straight y space equals space 8$

$space space therefore$ The required point be P (5, 8)

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