Find the ratio in which the line segment joining the points (6,

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 Multiple Choice QuestionsShort Answer Type

211. Find (he ratio in which the y-axis divides the line segment joining the points (5, -6) and (-1, -4). Also find the point of intersection.
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212. Find the ratio in which the line segment joining the points (6, 4) and (1, - 7) is divided by x-axis. Also find the point of intersection.



Fig. 7.31.Let the given points of the line segment be A(6, 4) and B(1

Fig. 7.31.
Let the given points of the line segment be A(6, 4) and B(1, -7).
Let the x-axis cut AB at the point ‘P’ in the ratio K : 1.
Then the co-ordinates of ‘P’ are given as

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Here, we have x1 = 6,    yx = 4
x2 = 1,    y2 = -7
and    m1 = K.    m2 = 1
So, coordinate of P are

open square brackets fraction numerator straight k left parenthesis 1 right parenthesis plus 1 left parenthesis 6 right parenthesis over denominator straight k plus 1 end fraction comma space fraction numerator straight k left parenthesis negative 7 right parenthesis plus 1 left parenthesis 4 right parenthesis over denominator straight k plus 1 end fraction close square brackets
equals open square brackets fraction numerator straight K plus 6 over denominator straight K plus 1 end fraction comma space fraction numerator straight K left parenthesis negative 7 right parenthesis plus 1 left parenthesis 4 right parenthesis over denominator straight K plus 1 end fraction close square brackets

But ‘P’ lies on x-axis. So its ordinate is 0.

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Putting straight K equals 4 over 7 comma space we get the co-ordinates of 'P' as 


equals straight P space open square brackets fraction numerator begin display style 4 over 7 plus 6 end style over denominator begin display style 4 over 7 plus 1 end style end fraction comma space fraction numerator negative 7 open parentheses begin display style 4 over 7 end style close parentheses plus 4 over denominator begin display style 4 over 7 plus 1 end style end fraction close square brackets equals straight P space open square brackets fraction numerator begin display style fraction numerator 4 plus 42 over denominator 7 end fraction end style over denominator begin display style fraction numerator 4 plus 7 over denominator 7 end fraction end style end fraction comma space fraction numerator negative 4 plus 4 over denominator begin display style fraction numerator 4 plus 7 over denominator 7 end fraction end style end fraction close square brackets
equals straight P space open square brackets 46 over 11 comma space 0 close square brackets

∴ The point of intersection of AB and the x-axis be open parentheses 46 over 11 comma space 0 close parentheses



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