[Here, we have x1Â = 6, Â Â Â y1Â = 1
x2Â = 9, Â Â Â y2Â = 4]
and the mid-point of the diagonal BD is
Here, we have x1Â = 8, Â Â Â y1Â = 2
x2Â = p, Â Â Â y2Â = 3]
Since, the co-ordinates of the mid-point of AC = Co-ordinates of the mid point of BD.