Let A(-2,-1), B(1, 0), C(4, 3) and D(1, 2) be the vertices of a parallelogram
Now, the mid-point of diagonal AC is
Here, we have
x1 = 2, y1 = —1
x2 = 4, y2 = 3
The mid-point of diagonal BD
[Here, we have
x1 = 1, y1 = 0
x2 = 1, y2 = 2]
∴ The mid-point of AC is the same as the midpoint of BD.
∆ ABCD is a parallelogram.
Test for Rectangle :
Clearly AC ≠ BD
So, ABCD is not a rectangle.