Let AOB be a right angle triangle, with hypotenuse AB. We take OB along x-axis and OA along y-axis.
Let ‘P’ be the mid-point of the hypotenuse. Then, the co-ordinates of A, B and Pare respectively A(0, n), B(m, 0) and P
Now,
Hence, P is equidistant from the vertices of ∆ABC.