Given points are A(-5, 7), B(-4, 5) and C(4, 5).
Here, we have
x1 = -5, y1 = 7
x2 = -4, y2 -5
and x3 = 4, y3 = 5
Area of ∆ABC
Hence area of the ∆ABC = 53 sq. units.
Find a relation between x and y such that the points P(x, y) is equidistant from A(5, 1) and B(-1, 5).
Find a relation between x and y such that A(x, y) is equidistant from the points (a + b, b - a) and (a - b, a + b).
Find a relation between x and y such that P(x, y) is equidistant from the points A(-2, 5) and B( 1, -3).