Find the smallest number by which each of the following numbers

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 Multiple Choice QuestionsShort Answer Type

11.

Is 216 a perfect cube? What is the number whose cube is 216?

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 Multiple Choice QuestionsLong Answer Type

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12.

Find the smallest number by which each of the following numbers must be divided to obtain a perfect cube. (i) 81 (ii) 128 (iii) 135 (iv) 192 (v) 704


(i) We have 81 = 3 x 3 x 3 x 3


(i) We have 81 = 3 x 3 x 3 x 3Grouping the prime factors of 81 into t
Grouping the prime factors of 81 into triples, we are left with 3.

∴ 81 is  not a perfect cube
Now,   [81] divided by3= [3 x 3 x 3 x 3] divided by3
or    27 = 3 x 3 x 3
i.e. 27 is a perfect cube
Thus, the required smallest number is 3

(ii) we have 128 = 2 x 2 x 2 x 2 x 2 x 2 x 2

(i) We have 81 = 3 x 3 x 3 x 3Grouping the prime factors of 81 into t
Grouping the prime factors of 128 into triples, we are left with 2
∴  128 is  not a perfect cube
Now,  [128] divided by2 = [2 x 2 x 2 x 2 x 2 x 2 x 2]divided by2
or         64 = 2 x 2 x 2 x 2 x 2 x 2
i.e. 64 is a perfect cube
∴  the smallest required number is 2.

(iii) we have 135 =  3 x 3 x 3 x 5

(i) We have 81 = 3 x 3 x 3 x 3Grouping the prime factors of 81 into t
Grouping the prime factors of 135 into triples, we are left over with 5.
∴  135 is not a perfect cube
Now, [135]divided by5 = [ 3 x 3 x 3 x 5] divided by5
or      27 = 3 x 3 x 3
i.e. 27 is a perfect cube.
Thus, the required smallest number is 5
(iv) We have 192 = 2 x 2 x 2 x 2 x 2 x 2 x 3

(i) We have 81 = 3 x 3 x 3 x 3Grouping the prime factors of 81 into t
Grouping the prime factors of 192 into triples, 3 is left over.
∴  192 is not a perfect cube.
Now,     [192] divided by3= [2 x 2 x 2 x 2 x 2 x 2 x 3]divided by3
or            64 = 2 x 2 x 2 x 2 x 2 x 2
i.e. 64 is a perfect cube.
Thus,  the required smallest number is 3.
(v) We have 704 = 2 x 2 x 2 x 2 x 2 x 2 x 11

(i) We have 81 = 3 x 3 x 3 x 3Grouping the prime factors of 81 into t
Grouping the prime factors of 704 into triples, 11 is left over
∴  [704]divided by11 = [2 x 2 x 2 x 2 x 2 x 2 x 11]divided by11
or    64 = 2 x 2 x 2 x 2 x 2 x 2
i.e. 64 is a perfect cube
Thus, the required smallest number is 11.


 

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 Multiple Choice QuestionsShort Answer Type

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