If x, y, z are different and from Mathematics Determinants

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 Multiple Choice QuestionsShort Answer Type

121.

Solve the equation
open vertical bar table row cell straight x plus straight a end cell cell space straight x end cell cell space straight x end cell row straight x cell space straight x plus straight a end cell cell space straight x end cell row straight x straight x cell space straight x plus straight a end cell end table close vertical bar space equals space 0 comma space space space straight a not equal to space 0.

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 Multiple Choice QuestionsLong Answer Type

122.

Solve:
open vertical bar table row cell straight x plus 1 end cell 2 3 row 3 cell straight x plus 2 end cell 1 row 1 2 cell straight x plus 3 end cell end table close vertical bar space equals 0

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123.

Prove that:
open vertical bar table row cell straight a squared plus 1 end cell cell straight a space straight b end cell cell straight a space straight c end cell row cell straight a space straight b end cell cell straight b squared plus 1 end cell cell straight b space straight c end cell row cell straight a space straight c end cell cell straight b space straight c end cell cell straight c squared plus 1 end cell end table close vertical bar space equals space 1 plus straight a squared plus straight b squared plus straight c squared.

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 Multiple Choice QuestionsShort Answer Type

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124.

If x, y, z are different and
increment space equals space open vertical bar table row straight x cell space space space space straight x squared end cell cell space 1 plus straight x cubed end cell row straight y cell space space space straight y squared end cell cell space 1 plus straight y cubed end cell row straight z cell space space straight z squared end cell cell space 1 plus straight z cubed end cell end table close vertical bar space equals space 0 comma space space then space show space that space 1 plus xyz space equals 0


increment space equals space open vertical bar table row straight x cell space space space straight x squared end cell cell space space 1 plus straight x cubed end cell row straight y cell space space space straight y squared end cell cell space space 1 plus straight y cubed end cell row straight z cell space space straight z squared end cell cell space space 1 plus straight z cubed end cell end table close vertical bar space equals space open vertical bar table row straight x cell space space space straight x squared end cell cell space 1 end cell row straight y cell space space straight y squared end cell cell space 1 end cell row straight z cell space space straight z squared end cell cell space 1 end cell end table close vertical bar plus space open vertical bar table row straight x cell space space space straight x squared end cell cell space space space straight x cubed end cell row straight y cell space space straight y squared end cell cell space space straight y cubed end cell row straight z cell space space straight z squared end cell cell space space straight z cubed end cell end table close vertical bar
space space space equals space open vertical bar table row 1 cell space space straight x end cell cell space space straight x squared end cell row 1 cell space space straight y end cell cell space space straight y squared end cell row 1 cell space space straight z end cell cell space space straight z squared end cell end table close vertical bar plus space straight x space straight y space straight z space space open vertical bar table row 1 cell space space straight x end cell cell space space straight x squared end cell row 1 cell space straight y end cell cell space space straight y squared end cell row 1 cell space straight z end cell cell space space straight z squared end cell end table close vertical bar
space equals space left parenthesis 1 plus xyz right parenthesis space open vertical bar table row 1 cell space space space straight x end cell cell space space space straight x squared end cell row 1 cell space space straight y end cell cell space space straight y squared end cell row 1 cell space space straight z end cell cell space space space straight z squared end cell end table close vertical bar
space equals space left parenthesis 1 plus xyz right parenthesis thin space left parenthesis straight x minus straight y right parenthesis thin space left parenthesis straight y minus straight z right parenthesis thin space left parenthesis straight z minus straight x right parenthesis
Now space increment space equals space 0
rightwards double arrow space space space space left parenthesis 1 plus xyz right parenthesis thin space left parenthesis straight x minus straight y right parenthesis thin space left parenthesis straight y minus straight z right parenthesis thin space left parenthesis straight z minus straight x right parenthesis
rightwards double arrow space space space space space space space 1 plus xyz space equals 0 space space space space space space space space space space space space space open square brackets table row cell because space space space straight x comma space straight y comma space straight z space are space all space different end cell row cell because space straight x space minus space straight y space not equal to 0 comma space space straight y minus straight z not equal to 0 comma space space straight z minus straight x not equal to 0 end cell end table close square brackets
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 Multiple Choice QuestionsLong Answer Type

125.

Prove that:
open vertical bar table row straight x cell space space space straight x squared end cell cell space space 1 plus px cubed end cell row straight y cell space space straight y squared end cell cell space space 1 plus py cubed end cell row straight z cell space space straight z squared end cell cell space space 1 plus pz cubed end cell end table close vertical bar space equals space left parenthesis 1 plus pxyz right parenthesis thin space left parenthesis straight x minus straight y right parenthesis thin space left parenthesis straight y minus straight z right parenthesis thin space left parenthesis straight z minus straight x right parenthesis
where p is any scalar.

76 Views

 Multiple Choice QuestionsShort Answer Type

126.

If space open vertical bar table row straight a cell space space straight a cubed end cell cell space space straight a to the power of 4 minus 1 end cell row straight b cell space straight b cubed end cell cell space space straight b to the power of 4 minus 1 end cell row straight c cell space straight c cubed end cell cell space space straight c to the power of 4 minus 1 end cell end table close vertical bar space equals space 0 comma
show that
a + b + c = abc(ab + bc + ca) where a , b , c are all different.

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127.

Let the three digit numbers A28,3B9 and 62C where A, B, and C are any integers between 0 and 9, be divisible by a fixed integer k. Show that the determinant
open vertical bar table row straight A cell space space 3 end cell cell space space space 6 end cell row 8 cell space 9 end cell cell space space straight C end cell row 2 cell space straight B end cell cell space space 2 end cell end table close vertical bar
is divisible by k.

151 Views

 Multiple Choice QuestionsLong Answer Type

128.

Prove that:
open vertical bar table row cell left parenthesis straight b plus straight c right parenthesis squared end cell cell straight a squared end cell cell straight a squared end cell row cell straight b squared end cell cell left parenthesis straight c plus straight a right parenthesis squared end cell cell straight b squared end cell row cell straight c squared end cell cell straight c squared end cell cell left parenthesis straight a plus straight b right parenthesis squared end cell end table close vertical bar space equals space 2 space abc space left parenthesis straight a plus straight b plus straight c right parenthesis cubed.

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129.

Prove that:
open vertical bar table row cell negative 2 straight a end cell cell space space space space straight a plus straight b end cell cell space space space straight a plus straight c end cell row cell straight b plus straight a end cell cell space space minus 2 straight b end cell cell space space space straight b plus straight c end cell row cell straight c plus straight a end cell cell space space straight c plus straight b end cell cell space space minus 2 straight c end cell end table close vertical bar space equals space 4 left parenthesis straight a plus straight b right parenthesis thin space left parenthesis straight b plus straight c right parenthesis thin space left parenthesis straight c plus straight a right parenthesis.


74 Views

 Multiple Choice QuestionsMultiple Choice Questions

130.

Let A be a square matrix of order 3 × 3, then | kA | is equal to 


  • k | A |
  • k2 | A |
  • 3| A |
  • 3| A |
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