Factorise the following expression:
121b2 - 88bc + 16c2
We have 121b2 - 88bc + 16c2 = (11b)2 - 2(11b)(4c) + (4c)2
= (11b - 4c)2 = (11b - 4c)(11b - 4c)
∴ 121b2 - 88bc + 16c2 = (11b - 4c)2 = (11b - 4c)(11b - 4c)