Factorise the expressions.
am2 + bm2 + bn2 + an2
We can take out m2 as common from the first two terms and n2 as common from the last two terms.
∴ am2 + bm2 + bn2 + an2 = m2(a + b) + n2(b + a)
= m2(a + b) + n2 (a + b)
= (a + b)[m2 + n2]