Evaluate the following integral using substitution. from Mathem

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 Multiple Choice QuestionsShort Answer Type

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91.

Evaluate the following integral using substitution.
integral subscript 0 superscript 1 fraction numerator straight x over denominator straight x squared plus 1 end fraction dx


Let I = integral subscript 0 superscript 1 fraction numerator straight x over denominator straight x squared plus 1 end fraction dx
Put straight x squared plus 1 space equals space straight y semicolon space space space space space space therefore space space 2 straight x space dx space equals space dy semicolon space space space space or space straight x space dx space equals space 1 half dy
When x = 2,  y = 5
When x = 3,  y = 10
therefore space space space straight I space space equals space 1 half integral subscript 5 superscript 10 dy over straight y space equals space 1 half open square brackets log space straight y close square brackets subscript 5 superscript 10 space equals space 1 half left square bracket log space 10 minus space log space 5 right square bracket space equals space 1 half log open parentheses 10 over 5 close parentheses space equals space 1 half log 2

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92.

Evaluate the following integral using substitution.



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93.

Evaluate the following definite integral:
integral subscript 0 superscript 1 straight x space straight e to the power of straight x squared end exponent space dx



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94.

Evaluate the following definite integral:
integral subscript 1 superscript 2 fraction numerator 1 over denominator straight x left parenthesis 1 plus log space straight x right parenthesis squared end fraction dx




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95.

Evaluate the following integral using substitution
integral subscript 0 superscript straight pi over 2 end superscript fraction numerator sin space straight x over denominator 1 plus cos squared straight x end fraction dx

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96.

Evaluate the following integral:
integral subscript straight pi over 6 end subscript superscript straight pi over 2 end superscript fraction numerator cosec space straight x space cotx over denominator 1 minus cosec squared straight x end fraction dx


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97.

Evaluate the following integral:
integral subscript 1 superscript 2 1 over straight x squared straight e to the power of negative 1 over straight x end exponent dx



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98.

Evaluate the following integral:
integral subscript 0 superscript 1 fraction numerator left parenthesis tan to the power of negative 1 end exponent straight x right parenthesis squared over denominator 1 plus straight x squared end fraction dx




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99.

Evaluate the following integral using substitution.
integral subscript 0 superscript 2 straight x space square root of straight x plus 2 end root dx.





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100.

Evaluate integral subscript negative 1 end subscript superscript 1 5 straight x to the power of 4 square root of straight x to the power of 5 plus 1 end root dx.

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