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 Multiple Choice QuestionsShort Answer Type

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121.

Evaluate: integral subscript 0 superscript straight pi over 4 end superscript space fraction numerator sinx space cosx over denominator cos squared straight x plus sin to the power of 4 straight x end fraction dx.


Let I = integral subscript 0 superscript straight pi over 4 end superscript fraction numerator sinx space cosx over denominator cos squared straight x plus sin to the power of 4 straight x end fraction dx space equals space integral subscript 0 superscript straight pi over 4 end superscript fraction numerator 4 space sinx space cosx over denominator 2 space left parenthesis 2 space cos squared straight x right parenthesis space plus space left parenthesis 2 space sin squared straight x right parenthesis squared end fraction dx

      equals space integral subscript 0 superscript straight pi over 4 end superscript fraction numerator 2 space sin 2 straight x over denominator 2 left parenthesis 1 plus cos 2 straight x right parenthesis plus left parenthesis 1 minus cos 2 straight x right parenthesis squared end fraction dx space equals space integral subscript 0 superscript straight pi over 4 end superscript fraction numerator 2 space sin 2 straight x over denominator 3 plus cos squared straight x end fraction dx

Put cos 2x =y,    ∴ –2 sin 2x dx = dy ⇒ 2 sin 2x dx = dy
When x = 0, y = cos 0 = 1

When straight x space equals space straight pi over 4 comma space space space straight y space equals space cos straight pi over 2 space equals space 0
therefore       I = -integral subscript 1 superscript 0 fraction numerator 1 over denominator 3 plus straight y squared end fraction dy space equals space minus integral subscript 1 superscript 0 fraction numerator 1 over denominator straight y squared plus left parenthesis square root of 3 right parenthesis squared end fraction dy space equals space minus fraction numerator 1 over denominator square root of 3 end fraction open square brackets tan to the power of negative 1 end exponent fraction numerator straight y over denominator square root of 3 end fraction close square brackets subscript 1 superscript 0
             equals negative fraction numerator 1 over denominator square root of 3 end fraction open square brackets tan to the power of negative 1 end exponent 0 space minus tan to the power of negative 1 end exponent fraction numerator 1 over denominator square root of 3 end fraction close square brackets space equals space minus fraction numerator 1 over denominator square root of 3 end fraction open square brackets 0 minus straight pi over 6 close square brackets space equals space fraction numerator straight pi over denominator 6 square root of 3 end fraction

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122.

Evaluate the following definite integral:
integral subscript 0 superscript straight pi over 4 end superscript fraction numerator sinx space cosx over denominator cos to the power of 4 straight x space plus space sin to the power of 4 straight x end fraction dx

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123.

Evaluate the following definite integral:
integral subscript straight pi over 6 end subscript superscript straight pi over 3 end superscript fraction numerator sinx plus cosx over denominator square root of sin space 2 straight x end root end fraction dx.

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124.

Evaluate the following definite integral:
integral subscript 0 superscript straight pi over 4 end superscript fraction numerator sinx plus cosx over denominator 9 plus 16 sin 2 straight x end fraction dx

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125.

Evaluate the following definite integral:
integral subscript 0 superscript straight pi over 2 end superscript sin space 2 straight x space tan to the power of negative 1 end exponent left parenthesis sin space straight x right parenthesis space dx.


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126.

Prove that integral subscript 0 superscript straight pi fraction numerator dx over denominator 5 plus 3 cosx end fraction space equals space straight pi over 4

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127.

Evaluate integral subscript 0 superscript straight pi fraction numerator dx over denominator 5 plus 4 space cosx end fraction.

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128.

Evaluate the following:
integral subscript 0 superscript straight pi over 2 end superscript fraction numerator dx over denominator 5 plus 4 space sinx end fraction

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129. Evaluate the following:
integral subscript 0 superscript straight pi fraction numerator 1 over denominator 5 plus 2 cosx end fraction dx
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130. Evaluate the following:
integral subscript 0 superscript straight pi fraction numerator 1 over denominator 6 minus cosx end fraction dx

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