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Integrals

Short Answer Type

131. Evaluate the following:
$integral subscript 0 superscript straight pi fraction numerator dx over denominator 1 plus sin space straight x end fraction$

Let I = $integral subscript 0 superscript straight pi fraction numerator dx over denominator 1 plus sinx end fraction$
Put $tan straight x over 2 space equals space straight t comma space space space or space space straight x over 2 equals space tan to the power of negative 1 end exponent straight t comma space space or space space straight x space equals space 2 tan to the power of negative 1 end exponent straight t space space rightwards double arrow space space space dx space space equals fraction numerator 2 over denominator 1 plus straight t squared end fraction dt$
$sinx space equals space fraction numerator 2 tan begin display style straight x over 2 end style over denominator 1 plus tan squared begin display style straight x over 2 end style end fraction space equals space fraction numerator 2 straight t over denominator 1 plus straight t squared end fraction$
When x = 0. t = tan 0 = 0
When $straight x space equals space straight pi comma space space space straight t space equals space tan straight pi over 2 space rightwards arrow space infinity$
$therefore$ $straight I space equals space integral subscript 0 superscript infinity fraction numerator begin display style fraction numerator 2 over denominator 1 plus straight t squared end fraction end style dt over denominator 1 plus begin display style fraction numerator 2 straight t over denominator 1 plus straight t squared end fraction end style end fraction space equals space integral subscript 0 superscript infinity fraction numerator 2 over denominator 1 plus straight t squared plus 2 straight t end fraction dt space equals space 2 integral subscript 0 superscript infinity fraction numerator dt over denominator left parenthesis straight t plus 1 right parenthesis squared end fraction space equals 2 integral subscript 0 superscript infinity left parenthesis straight t plus 1 right parenthesis to the power of negative 2 end exponent dt$
$equals space 2 open square brackets fraction numerator left parenthesis straight t plus 1 right parenthesis to the power of negative 1 end exponent over denominator negative 1 end fraction close square brackets subscript 0 superscript infinity space equals space minus 2 open square brackets fraction numerator 1 over denominator straight t plus 1 end fraction close square brackets subscript 0 superscript infinity space equals space minus 2 open square brackets Lt with straight t rightwards arrow infinity below fraction numerator 1 over denominator straight t plus 1 end fraction minus fraction numerator 1 over denominator 0 plus 1 end fraction close square brackets space equals space minus 2 left square bracket 0 minus 1 right square bracket space equals space 2$

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132. Evaluate the following:

integral subscript 0 superscript 1 sin to the power of negative 1 end exponent open parentheses fraction numerator 2 straight x over denominator 1 plus straight x squared end fraction close parentheses dx

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133. Evaluate the following:

integral subscript 0 superscript 1 cos to the power of negative 1 end exponent open parentheses fraction numerator 1 minus straight x squared over denominator 1 plus straight x squared end fraction close parentheses dx

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134. Evaluate the following:

integral subscript 0 superscript 1 tan to the power of negative 1 end exponent open parentheses fraction numerator 2 straight x over denominator 1 minus straight x squared end fraction close parentheses dx

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135. Evaluate the following:

integral subscript 0 superscript 2 straight pi end superscript straight e to the power of straight x space sin open parentheses straight pi over 4 plus straight x over 2 close parentheses dx.

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136. Evaluate the following:

integral subscript 1 superscript 2 open parentheses 1 over straight x minus fraction numerator 1 over denominator 2 straight x squared end fraction close parentheses space straight e to the power of 2 straight x end exponent dx

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137. Evaluate the following:

integral subscript straight pi over 2 end subscript superscript straight pi straight e to the power of straight x open parentheses fraction numerator 1 minus sinx over denominator 1 minus cosx end fraction close parentheses dx

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138. Evaluate the following:

integral subscript 0 superscript 2 straight pi end superscript space straight e to the power of straight x over 2 end exponent space sin space open parentheses straight x over 2 plus straight pi over 4 close parentheses dx

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139.

Evaluate the following:
$integral subscript 0 superscript 2 straight pi end superscript straight e to the power of straight x cos open parentheses straight pi over 4 plus straight x over 2 close parentheses dx.$

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Multiple Choice Questions

140.

The value of the integral $integral subscript 1 third end subscript superscript 1 fraction numerator left parenthesis straight x minus straight x cubed right parenthesis to the power of begin display style 1 third end style end exponent over denominator straight x to the power of 4 end fraction dx$

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