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 Multiple Choice QuestionsShort Answer Type

191.

Show that:
integral subscript straight pi over 4 end subscript superscript straight pi over 4 end superscript open vertical bar sin space straight x close vertical bar dx space equals space 2 minus square root of 2



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 Multiple Choice QuestionsLong Answer Type

192.

Show that:
integral subscript negative 1 end subscript superscript 3 over 2 end superscript open vertical bar straight x space sinπ space straight x close vertical bar space dx space equals space 3 over straight pi plus 1 over straight pi squared



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 Multiple Choice QuestionsShort Answer Type

193.

Show that:
integral subscript 0 superscript 2 straight x square root of 2 minus straight x end root space equals fraction numerator 16 square root of 2 over denominator 15 end fraction

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194.

By using the properties of definite integrals, evaluate the following integral:
integral subscript 0 superscript 1 space straight x space left parenthesis 1 minus straight x right parenthesis to the power of straight n space dx

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195.

By using the properties of definite integrals, evaluate the following integral:
integral subscript 0 superscript straight pi over 2 end superscript fraction numerator sinx minus cosx over denominator 1 plus sinxcosx end fraction dx

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196.

Show that:
integral subscript 0 superscript straight pi over 2 end superscript 2 straight x space log space tanx space dx space equals space 0


Let I = integral subscript 0 superscript straight pi over 2 end superscript sin space 2 straight x space log space tanx space dx
therefore space space space straight I space equals space integral subscript 0 superscript straight pi over 2 end superscript sin space 2 open parentheses straight pi over 2 minus straight x close parentheses. space log space tan open parentheses straight pi over 2 minus straight x close parentheses dx space space space rightwards double arrow space space straight I space equals space integral subscript 0 superscript straight pi over 2 end superscript sin space 2 straight x space log space cot space straight x space dx
rightwards double arrow space space straight I space equals space integral subscript 0 superscript straight pi over 2 end superscript space sin space 2 straight x space log open parentheses 1 over tanx close parentheses dx space space rightwards double arrow space space straight I space equals space integral subscript 0 superscript straight pi over 2 end superscript sin space 2 straight x left parenthesis log space 1 space minus space log space tanx right parenthesis space dx
rightwards double arrow space straight I space equals space integral subscript 0 superscript straight pi over 2 end superscript sin space 2 straight x left parenthesis 0 minus log space tanx right parenthesis space dx space rightwards double arrow space space straight I space equals space minus integral subscript 0 superscript straight pi over 2 end superscript sin space 2 straight x space log space tanx space dx
rightwards double arrow space space space straight I equals space minus straight I                                                              open square brackets because space space of space left parenthesis 1 right parenthesis close square brackets
rightwards double arrow space space space space 2 space straight I space equals space 0 space space space rightwards double arrow space space space straight I space equals space 0

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197.

By using the properties of definite integrals, evaluate the following integral:
integral subscript 0 superscript straight pi over 2 end superscript left parenthesis 2 space log space sinx space minus space log space sin space 2 straight x right parenthesis space dx

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198.

Show that:
integral subscript 0 superscript straight pi fraction numerator straight x space tanx over denominator secx space plus space cosx end fraction dx space equals space straight pi squared over 4

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199.

Show that:
integral subscript 0 superscript infinity log space open parentheses straight x plus 1 over straight x close parentheses. space fraction numerator dx over denominator 1 plus straight x squared end fraction space equals space straight pi space log space 2

132 Views

200.

Show that:
integral subscript 0 superscript 1 fraction numerator log space left parenthesis 1 plus straight x right parenthesis over denominator 1 plus straight x squared end fraction space equals space straight pi over 8 space log space 2

120 Views

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