Evaluate  from Mathematics Integrals

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 Multiple Choice QuestionsShort Answer Type

231. space F i n d space colon integral fraction numerator left parenthesis 2 x minus 5 right parenthesis e to the power of 2 x end exponent over denominator left parenthesis 2 x minus 3 right parenthesis end fraction d x
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232. Find space colon integral fraction numerator straight x squared plus straight x plus 1 over denominator left parenthesis straight x squared plus 1 right parenthesis left parenthesis straight x plus 2 right parenthesis end fraction dx
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233. Evaluate space colon space integral subscript negative 2 end subscript superscript 2 fraction numerator straight x squared over denominator 1 plus 5 to the power of straight x end fraction dx.
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234. Find colon space integral left parenthesis straight x plus 3 right parenthesis square root of 3 minus 4 straight x minus straight x squared space end root space dx.
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235.

Find the integrating factor for the following differential equation:straight x space log space straight x dy over dx space plus space straight y space equals space 2 logx space

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236.

Evaluate: integral subscript 0 superscript straight pi divided by 2 end superscript fraction numerator sin squared straight x over denominator sinx plus cosx end fraction dx.

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237.

Evaluate integral subscript negative 1 end subscript superscript 2 left parenthesis straight e to the power of 3 straight x end exponent plus 7 straight x minus 5 right parenthesis dx


integral subscript negative 1 end subscript superscript 2 left parenthesis straight e to the power of 3 straight x end exponent plus 7 straight x minus 5 right parenthesis dx
Here space straight f left parenthesis straight x right parenthesis space equals space straight e to the power of 3 straight x end exponent plus 7 straight x minus 5
straight a space equals negative 1 comma space space straight b equals space 2 comma space space straight h space equals space fraction numerator straight b minus straight a over denominator straight n end fraction equals 3 over straight n
By space definition space integral subscript negative 1 end subscript superscript 2 left parenthesis straight e to the power of 3 straight x end exponent plus 7 straight x minus 5 right parenthesis dx space equals limit as straight n rightwards arrow infinity of sum from straight r equals 1 to straight n of straight h. straight f left parenthesis straight a plus rh right parenthesis
limit as straight n rightwards arrow infinity of sum from straight r equals 1 to straight n of straight h. straight f left parenthesis negative 1 plus rh right parenthesis equals limit as straight n rightwards arrow infinity of sum from straight r equals 1 to straight n of straight h. open parentheses straight e to the power of 3 left parenthesis negative 1 plus rh right parenthesis end exponent plus 7 left parenthesis negative 1 plus rh right parenthesis minus 5 close parentheses
space space space equals space limit as straight n rightwards arrow infinity of open square brackets straight h. straight e to the power of negative 3 end exponent. space straight e to the power of 3 straight h end exponent open parentheses 1 plus straight e to the power of 3 straight h end exponent plus straight e to the power of 6 straight h end exponent plus.. plus straight e to the power of 3 nh end exponent close parentheses plus 7 straight h squared left parenthesis 1 plus 2 plus 3 plus.. plus straight n right parenthesis minus 12 nh close square brackets
space space space equals space limit as straight n rightwards arrow infinity of open square brackets he to the power of 3 straight h end exponent over straight e cubed cross times fraction numerator straight e to the power of 3 nh end exponent minus 1 over denominator straight e to the power of 3 straight h end exponent minus 1 end fraction plus 7 straight h squared fraction numerator straight n left parenthesis straight n plus 1 right parenthesis over denominator 2 end fraction minus 12 nh close square brackets
space space space equals limit as straight n rightwards arrow infinity of open square brackets open parentheses fraction numerator 3 straight e to the power of 3 cross times begin display style 3 over straight n end style end exponent over denominator ne cubed end fraction cross times open parentheses straight e to the power of 3 straight n cross times 3 over straight n minus 1 end exponent close parentheses cross times open parentheses fraction numerator 3 straight h over denominator straight e to the power of 3 straight h end exponent minus 1 end fraction close parentheses cross times fraction numerator straight n over denominator 3 cross times 3 end fraction close parentheses plus 63 over straight n squared cross times fraction numerator straight n left parenthesis straight n plus 1 right parenthesis over denominator 2 end fraction minus 12 cross times 3 close square brackets
Now applying the limit we get,

equals fraction numerator straight e to the power of 9 minus 1 over denominator 3 straight e cubed end fraction plus 63 over 2 minus 36
equals fraction numerator straight e to the power of 9 minus 1 over denominator 3 straight e cubed end fraction minus 9 over 2
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238.

Evaluate:
integral fraction numerator straight x squared over denominator straight x to the power of 4 plus straight x squared minus 2 end fraction dx

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239.

Evaluate: integral fraction numerator left parenthesis straight x plus 3 right parenthesis straight e to the power of straight x over denominator left parenthesis straight x plus 5 right parenthesis cubed end fraction dx

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240.

Three schools X, Y, and Z organized a fete (mela) for collecting funds for flood victims in which they sold hand-held fans, mats and toys made from recycled material, the sale price of each being Rs. 25, Rs. 100 andRs. 50 respectively. The following table shows the number of articles of each type sold:
School/Article                     School X                   School Y                School Z
Hand-held fans                         30                         40                         35
      Mats                                  12                         15                         20
       Toys                                 70                         55                         75
Using matrices, find the funds collected by each school by selling the above articles and the total funds collected. Also write any one value generated by the above situation. 

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