If the vertices of a· triangle are A(0, 4, 1), B(2, 3, - 1

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 Multiple Choice QuestionsMultiple Choice Questions

151.

Locus of centroid of triangle whose vertices are acost, asint bsint, - bcost and (1, 0) where t is a parameter is

  • (3x - 1)2 + (3y)2 = a2 - b2

  • (3x - 1)2 + (3y)2 = a2 + b2

  • (3x + 1)2 + (3y)2 = a2 + b2

  • (3x + 1)2 + (3y)2 = a2 - b2


152.

A house of height 100 m subtends a right angle at the window of an opposite house. If the height of the window be 64 m, then the distance between the two houses is

  • 48 m

  • 36 m

  • 54 m

  • 72 m


153.

The distance travelled by a motor car in t seconds after the brakes are applied is s feet, wheres = 22t - 12t2. The distance travelled by the car before it stops, is

  • 10.08 ft

  • 10ft

  • 11ft

  • 11.5ft


154.

The sides of triangle are in the ratio 1 : √3 : 2, then the angles of the triangle are in ratio

  • 1 : 3 : 5

  • 2 : 3 : 1

  • 3 : 2 : 1

  • 1 : 2 : 3


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155.

If the distance between the plane Ax - 2 y + z = d and the plane containing the lines x - 12 = y - 23 = z - 34 and x - 23 = y - 34 = z - 45 is 6, then d is equal to

  • 3

  • 4

  • 6

  • 1


156.

The normal at (a, 2a) on y2 = 4ax, meets the curve again at (at, 2at ), then the value of t is

  • - 1

  • 1

  • - 3

  • 3


157.

The shortest distance from the plane 12x + y + 3z = 327 to the sphere x2 + y2 + z2 + 4x - 2y - 6z = 155 is

  • 13

  • 26

  • 39

  • 41413


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158.

If the vertices of a· triangle are A(0, 4, 1), B(2, 3, - 1) and C(4, 5, 0), then the orthocentre of ABC, is

  • (4, 5, 0)

  • (2, 3, - 1)

  • (- 2, 3, - 1)

  • (2, 0, 2)


B.

(2, 3, - 1)

Given, vertices of ABC are A(0, 4, 1), 8(2, 3, - 1) and C (4, 5, 0).

Now, AB = 2 - 02 + 3 - 42 + - 1 - 12               = 4 + 1 + 4 = 3BC = 4 - 22 + 5 - 32 + 0 - 12     = 4 + 4 + 1 = 3and CA = 4 - 02 + 5 - 42 + 0 - 12            = 16 + 1 + 1            = 32 AB2 +BC2 = AC2 ABC  is a right angled triangle.

We know that, the orthocentre of a right angled triangle is the vertex containing 90° angle.

Thus, Orthocentre is point B (2, 3, - 1).


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159.

The normals at three points· P,Q and R of the parabola y2 = 4ax meet at (h, k). The centroid of the PQR lies on

  • x = 0

  • y = 0

  • x = - a

  • y = a


160.

A tower AB leans towards West making an angle α with the vertical. The angular elevation of B, the top most point of the tower is β as observed from a point C due East of A at a distance 'd' from A. If the angular elevation of B from a point D due East of C at a distance 2d from C is r, then 2tanα can be given as

  • 3cotβ - 2cotγ

  • 3cotγ - 2cotβ

  • 3cotβ - cotγ

  • cotβ - 3cotγ


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