Prove the following identity: from Mathematics Introduction to

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 Multiple Choice QuestionsShort Answer Type

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391.

Prove the following identity:
fraction numerator cosecθ over denominator cosecθ minus 1 end fraction plus fraction numerator cosecθ over denominator cosecθ plus 1 end fraction equals 2 plus 2 tan squared straight theta.






straight L. straight H. straight S. space equals fraction numerator cosecθ over denominator cosecθ minus 1 end fraction plus fraction numerator cosec space straight theta over denominator cosecθ plus 1 end fraction
equals space fraction numerator cosecθ left parenthesis cosecθ plus 1 right parenthesis plus cosecθ left parenthesis cosecθ minus 1 right parenthesis over denominator left parenthesis cosecθ minus 1 right parenthesis thin space left parenthesis cosecθ plus 1 right parenthesis end fraction
equals space fraction numerator cosec squared straight theta plus cosecθ plus cosec squared straight theta minus cosecθ over denominator cosec squared straight theta minus 1 end fraction
equals space fraction numerator 2 space cosec squared straight theta over denominator cot squared straight theta end fraction space equals space fraction numerator 2 over denominator cot squared straight theta end fraction cosec squared straight theta
equals 2 space tan squared straight theta space left parenthesis cot squared straight theta plus 1 right parenthesis
equals space 2 space tan squared straight theta. space cot squared straight theta plus 2 space tan squared straight theta
space equals space 2 plus 2 space tan squared straight theta
equals space straight R. straight H. straight S.
Hence, L.H.S. = R.H.S.
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392.

Prove the following identity:
square root of fraction numerator 1 plus cosθ over denominator 1 minus cosθ end fraction end root equals space cosecθ plus cotθ.






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 Multiple Choice QuestionsLong Answer Type

393.

Prove the following identity:
fraction numerator tanθ over denominator 1 minus cotθ end fraction plus fraction numerator cotθ over denominator 1 minus tanθ end fraction equals 1 plus tanθ plus cotθ.







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 Multiple Choice QuestionsShort Answer Type

394.

What is the value of (Cos267o - sin2 23o)?


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395.

If 4 tan θ = 3, evaluate 4 sin θ - cos θ + 14 sin θ + cos θ - 1


396.

If tan 2A = cot (A - 18o), where 2A is an angle, find the value of A


 Multiple Choice QuestionsLong Answer Type

397.

Prove that sin A - 2sin3 A2 cos3 A - cos A = tan A.


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