Important Questions of Inverse Trigonometric Functions Mathematics | Zigya
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    Mathematics : Inverse Trigonometric Functions

    Multiple Choice QuestionsShort Answer Type

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    31. Show that cos (sin–1.x) = sin (cos–1x) = square root of 1 minus straight x squared end root space for space open vertical bar straight x close vertical bar space space less or equal than space 1
    204 Views
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    32. If sin–1x = y, then

    (A) 0 ≥ y ≥ straight pi        (B)  negative straight pi over 2 less or equal than straight Y less or equal than straight pi over 2

    (C) 0  < y < straight pi       (D)  negative straight pi over 2 less than straight y less than straight pi over 2      
    265 Views
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    33. tan to the power of negative 1 end exponent square root of 3 minus s e c to the power of negative 1 end exponent left parenthesis negative 2 right parenthesis is equal

    (A) straight pi    (B) negative straight pi over 3   (C) straight pi over 3   (D) fraction numerator 2 straight pi over denominator 3 end fraction
    130 Views
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    34. Find the value of sin–1 open parentheses sin space fraction numerator 3 straight x over denominator 5 end fraction close parentheses.
    100 Views
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    35. Find the values of each of the expressions :

    sin to the power of negative 1 end exponent open parentheses sin fraction numerator 2 straight pi over denominator 3 end fraction close parentheses
    110 Views
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    36. Find the values of each of the expressions :

    tan to the power of negative 1 end exponent open parentheses tan space fraction numerator 3 straight pi over denominator 4 end fraction close parentheses
    108 Views
    Answer
    37.

    Find the value of the following :

    cos to the power of negative 1 end exponent open parentheses cos space fraction numerator 13 straight pi over denominator 6 end fraction close parentheses

    109 Views
    Answer
    38.

    Find the value of the following :

    tan to the power of negative 1 end exponent open parentheses tan space fraction numerator 7 space straight pi over denominator 6 end fraction close parentheses

    152 Views
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    39. Using principle value, evaluate the following :

    cos to the power of negative 1 end exponent open parentheses cos fraction numerator 2 straight pi over denominator 3 end fraction close parentheses plus sin to the power of negative 1 end exponent open parentheses sin space fraction numerator 2 straight pi over denominator 3 end fraction close parentheses
    133 Views
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    40. If space sin open parentheses sin to the power of negative 1 end exponent 1 fifth plus cos to the power of negative 1 end exponent straight x close parentheses equals 1  then find the value of x.
    108 Views
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