Find the value of tan-1  from Mathematics Inverse Trigonometri

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsShort Answer Type

21. Find the principal values of the following

tan-1(- 1)


257 Views

22. Find the principal values of the following

sec to the power of negative 1 end exponent open parentheses fraction numerator 2 over denominator square root of 3 end fraction close parentheses


133 Views

23. Find the principal values of the following

cot to the power of negative 1 end exponent open parentheses square root of 3 close parentheses


121 Views

24. Find the principal values of the following

cos to the power of negative 1 end exponent open parentheses negative fraction numerator 1 over denominator square root of 2 end fraction close parentheses


118 Views

Advertisement
25. Find the principal values of the following

cos e c to the power of negative 1 end exponent left parenthesis negative square root of 2 right parenthesis


110 Views

26. Evaluate

sin open square brackets 2 space cos to the power of negative 1 end exponent open parentheses negative 3 over 5 close parentheses close square brackets
266 Views

27. Evaluate  sin[ tan-1 (- 1) ]



125 Views

Advertisement

28. Find the value of tan-1 open square brackets 2 space cos space open parentheses 2 space sin to the power of negative 1 end exponent 1 half close parentheses close square brackets


Let space space space space straight y space equals space sin to the power of negative 1 end exponent 1 half space space space space space space where space space minus straight pi over 2 less or equal than straight r less or equal than straight pi over 2
therefore space space space space space space sin space space straight y space equals space 1 half space space space space space space where space space minus straight pi over 2 less or equal than straight r less or equal than straight pi over 2
therefore space space space space space space space straight y space equals straight pi over 6
therefore space space space space space space space tan to the power of negative 1 end exponent open square brackets 2 space cos space open parentheses 2 space sin to the power of negative 1 end exponent space 1 half close parentheses close square brackets equals space tan to the power of negative 1 end exponent space open square brackets 2 space cos space open parentheses 2 cross times straight pi over 6 close parentheses close square brackets
space space space space space space space space space space space space tan space to the power of negative 1 end exponent open square brackets 2 space cos straight pi over 3 close square brackets equals tan to the power of negative 1 end exponent open square brackets 2 cross times 1 half close square brackets equals tan to the power of negative 1 end exponent left parenthesis 1 right parenthesis equals straight pi over 4
107 Views

Advertisement
Advertisement
29. Find the value of the following :

space space space space space space space space tan to the power of negative 1 end exponent left parenthesis 1 right parenthesis plus cos to the power of negative 1 end exponent open parentheses negative 1 half close parentheses plus sin to the power of negative 1 end exponent open parentheses negative 1 half close parentheses
146 Views

30. Find the value of the following :

cos to the power of negative 1 end exponent open parentheses 1 half close parentheses plus 2 space sin to the power of negative 1 end exponent open parentheses 1 half close parentheses
123 Views

Advertisement