Find the value of the following: from Mathematics Inverse Trigo

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 Multiple Choice QuestionsShort Answer Type

111.

Write the value of open parentheses 2 tan to the power of negative 1 end exponent 1 fifth close parentheses

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112.

Find the value of the following:
tan 1 half open square brackets sin to the power of negative 1 end exponent fraction numerator 2 straight x over denominator 1 plus straight x squared end fraction plus cos to the power of negative 1 end exponent fraction numerator 1 minus straight y squared over denominator 1 plus straight y squared end fraction close square brackets comma space open vertical bar straight x close vertical bar space less than 1 comma space space straight y greater than 0 space and space xy less than 1


We know that:
sin to the power of negative 1 end exponent fraction numerator 2 straight x over denominator 1 plus straight x squared end fraction equals 2 tan to the power of negative 1 end exponent straight x space for space open vertical bar straight x close vertical bar less or equal than 1 space... left parenthesis 1 right parenthesis
cos to the power of negative 1 end exponent fraction numerator 1 minus straight y squared over denominator 1 plus straight y squared end fraction equals 2 tan to the power of negative 1 end exponent straight y space for space straight y greater than 0 space... left parenthesis 2 right parenthesis
therefore space space sin to the power of negative 1 end exponent fraction numerator 2 straight x over denominator 1 plus straight x squared end fraction plus cos to the power of negative 1 end exponent fraction numerator 1 minus straight y squared over denominator 1 plus straight y squared end fraction equals 2 tan to the power of negative 1 end exponent straight x plus 2 tan to the power of negative 1 end exponent straight y.
rightwards double arrow space tan 1 half open square brackets sin to the power of negative 1 end exponent fraction numerator 2 straight x over denominator 1 plus straight x squared end fraction plus cos to the power of negative 1 end exponent fraction numerator 1 minus straight y squared over denominator 1 plus straight y squared end fraction close square brackets
equals tan 1 half left parenthesis 2 tan to the power of negative 1 end exponent straight x plus 2 tan to the power of negative 1 end exponent straight y right parenthesis
equals tan left parenthesis tan to the power of negative 1 end exponent straight x plus tan to the power of negative 1 end exponent straight y right parenthesis
equals tan open parentheses tan to the power of negative 1 end exponent fraction numerator straight x plus straight y over denominator 1 minus xy end fraction close parentheses space space open square brackets because tan to the power of negative 1 end exponent straight x plus tan to the power of negative 1 end exponent straight y equals tan to the power of negative 1 end exponent fraction numerator straight x plus straight y over denominator 1 minus xy end fraction comma space for space xy less than 1 close square brackets
equals fraction numerator straight x plus straight y over denominator 1 minus xy end fraction

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113.

Prove that tan to the power of negative 1 end exponent open parentheses 1 half close parentheses plus tan to the power of negative 1 end exponent open parentheses 1 fifth close parentheses plus tan to the power of negative 1 end exponent open parentheses 1 over 8 close parentheses space equals straight pi over 4

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114.

If a line makes angles 90° and 60° respectively with the positive directions of x and y axes, find the angle which it makes with the positive direction of the z-axis.

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115.
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116.

Prove that 

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117.

Find the value of tan-1 3 - cot-1 (-3)


118.

Prove that:3 sin-1 x  = sin-1 (3x - 4x3), X  -12, 12


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119.

Evaluate:   sinπ3 - sin-1 12


 Multiple Choice QuestionsLong Answer Type

120.

Prove the following:

tan-113 + tan-115 + tan-117 + tan-118


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