Solve the following linear equation:
∵ LCM of 3 and 5 is 15.
∴ Multiplying both sides by 15, we have
or 5(x-5) = 3(x-3)
or 5x - 25 = 3x - 9
Transposing (-25) to RHS and 3x to LHS, we have
5x -3x = -9 + 25
or 2x = 16
or (Dividing both sides by 2)
∴ x = 8
Check: LHS =
=
=
RHS =
=
∴ LHS = RHS
Simplify and solve the following linear equation:
3(5z - 7) - 2(9z - 11) = 4(8z - 13) - 17