Solve the following linear equation: from Mathematics Linear Eq

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 Multiple Choice QuestionsShort Answer Type

91.

Solve the following linear equation:

x over 2 minus 1 fifth equals x over 3 plus 1 fourth

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92.

Solve the following linear equation:

straight n over 2 minus fraction numerator 3 straight n over denominator 4 end fraction plus fraction numerator 5 straight n over denominator 6 end fraction equals 21

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93.

Solve the following linear equation:

straight x plus 7 minus fraction numerator 8 straight x over denominator 3 end fraction equals 17 over 6 minus fraction numerator 5 straight x over denominator 2 end fraction

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94.

Solve the following linear equation:

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95.

Solve the following linear equation:

fraction numerator 3 t minus 2 over denominator 4 end fraction minus fraction numerator 2 t plus 3 over denominator 3 end fraction equals 2 over 3 minus t



fraction numerator 3 t minus 2 over denominator 4 end fraction minus fraction numerator 2 t plus 3 over denominator 3 end fraction equals 2 over 3 minus t

∵     LCM of 4 and 3 is 12.

∴        Multiplying both sides by 12, we have

          12 cross times fraction numerator 3 t minus 2 over denominator 4 end fraction minus 12 cross times fraction numerator 2 t plus 3 over denominator 3 end fraction equals 12 cross times 2 over 3 minus 12 cross times t

or         3(3t-2) - 4(2t+3) = (4 cross times2) - 12t

or            9t - 6 - 8t - 12 = 8 - 12t

or         (9-8)t - (6+12) = 8 - 12t

or                       t-18 = 8 - 12t

Transposing -18 to RHS and -12t to LHS, we have

                       t +12t = 8 + 18

or                        13t = 26

or                             t equals 26 over 13                (Dividing both sides by 2)

∴                              t = 2

Check:                  LHS = fraction numerator 3 t minus 2 over denominator 4 end fraction minus fraction numerator 2 t plus 3 over denominator 3 end fraction

                                 = space space space space fraction numerator 3 cross times 2 minus 2 over denominator 4 end fraction minus fraction numerator 2 cross times 2 plus 3 over denominator 3 end fraction
                               
                                  = fraction numerator 6 minus 2 over denominator 4 end fraction minus fraction numerator 4 plus 3 over denominator 3 end fraction
                                
                                  = 4 over 4 minus 7 over 3 equals 1 minus 7 over 3
                                 
                                   = fraction numerator 3 minus 7 over denominator 3 end fraction equals negative 4 over 3

                         RHS = 2 over 3 minus t
                              
                             =space space space space space space space 2 over 3 minus 2 equals fraction numerator 2 minus 6 over denominator 3 end fraction
                             
                             = fraction numerator negative 4 over denominator 3 end fraction
                    
 

∴                       LHS = RHS



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96.

Solve the following linear equation:

m minus fraction numerator m minus 1 over denominator 2 end fraction equals 1 minus fraction numerator m minus 2 over denominator 3 end fraction

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97.

Simplify and solve the following linear equation:

3(t-3) = 5(2t+1)

281 Views

98.

Simplify and solve the following linear equation:

15(y-4) - 2(y-9) + 5(y+6) =0

322 Views

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99.

Simplify and solve the following linear equation:

3(5z - 7) - 2(9z - 11) = 4(8z - 13) - 17

256 Views

100.

Simplify and solve the following linear equation:

0.25(4f-3) = 0.05(10f - 9)

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