Solve the following linear equation: from Mathematics Linear Eq

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 Multiple Choice QuestionsShort Answer Type

91.

Solve the following linear equation:

x over 2 minus 1 fifth equals x over 3 plus 1 fourth

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92.

Solve the following linear equation:

straight n over 2 minus fraction numerator 3 straight n over denominator 4 end fraction plus fraction numerator 5 straight n over denominator 6 end fraction equals 21

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93.

Solve the following linear equation:

straight x plus 7 minus fraction numerator 8 straight x over denominator 3 end fraction equals 17 over 6 minus fraction numerator 5 straight x over denominator 2 end fraction

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94.

Solve the following linear equation:

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95.

Solve the following linear equation:

fraction numerator 3 t minus 2 over denominator 4 end fraction minus fraction numerator 2 t plus 3 over denominator 3 end fraction equals 2 over 3 minus t


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96.

Solve the following linear equation:

m minus fraction numerator m minus 1 over denominator 2 end fraction equals 1 minus fraction numerator m minus 2 over denominator 3 end fraction


straight m minus fraction numerator straight m minus 1 over denominator 2 end fraction equals 1 minus fraction numerator straight m minus 2 over denominator 3 end fraction

Since, LCM of 2 and 3 is 6.

∴  Multiplying both sides by 6, we have

           6 cross times m - 6 cross timesfraction numerator space space straight m minus 1 over denominator 3 end fraction space equals space 6 cross times 1 minus 6 cross times fraction numerator straight m minus 2 over denominator 3 end fraction

or                  6m -3(m-1) = 6 - 2(m-2)

or                      6m - 3m + 3 = 6 -2m + 4

or                     (6-3)m + 3 = (6+4) - 2m

or                            3m + 3 = 10 - 2m

Transposing 3 to RHS and -2m to LHS, we have

                           3m + 2m = 10 - 3

or                                  5m =7

or                                 straight m equals 7 over 5       (Dividing both sides by 5)

Check:                       LHS = straight m minus fraction numerator straight m minus 1 over denominator 2 end fraction

                                      = 7 over 5 minus fraction numerator begin display style 7 over 5 end style minus 1 over denominator 2 end fraction equals 7 over 5 minus fraction numerator begin display style 2 over 5 end style over denominator 2 end fraction

                                      = 7 over 5 minus 2 over 5 cross times 1 half

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                                RHS = 1 minus fraction numerator straight m minus 2 over denominator 3 end fraction

                                      = 1 minus fraction numerator begin display style 7 over 5 end style minus 2 over denominator 3 end fraction equals 1 minus fraction numerator begin display style fraction numerator negative 3 over denominator 5 end fraction end style over denominator 3 end fraction
                                     
                                      = space space 1 plus 3 over 5 cross times 1 third

                                      = 1 plus 1 fifth equals 6 over 5

∴                                LHS = RHS

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97.

Simplify and solve the following linear equation:

3(t-3) = 5(2t+1)

281 Views

98.

Simplify and solve the following linear equation:

15(y-4) - 2(y-9) + 5(y+6) =0

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99.

Simplify and solve the following linear equation:

3(5z - 7) - 2(9z - 11) = 4(8z - 13) - 17

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100.

Simplify and solve the following linear equation:

0.25(4f-3) = 0.05(10f - 9)

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