A number is such that it is as much greater than 45 as it is less than 75. Find the number.
A number is 20 greater than the sum of its one-third and one-ninth. Find the number.
Let the number be X .
Then, required equation
=> X - (X/3 + X/9) = 20
=> X - 4x/9 = 20
=> (9X - 4X)/9 = 20
=> 5X/9 = 20
=> 5X = 20 × 9
=> X = 36
The numerator of a fraction is 2 less than its denominator. If 2 is subtracted from the numerator and 1 is the added to the denominator then the fraction becomes 2/7. Find the fraction.
If 1 is subtracted from both sides of x + 1 = 5, then we have:
x = 5 – 1
x + 2 4
x = 1 – 6