∵ Ray QP stands on line ST
∴ ∠PQS + ∠PQR = 180° ...(1)
| Linear Pair Axiom
∵ Ray RP stands on line ST
∴ ∠PRQ + ∠PRT = 180° ...(2)
| Linear Pair Axiom
From (1) and (2), we obtain
∠PQS + ∠PQR = ∠PRQ + ∠PRT
⇒ ∠PQS = ∠PRT.
| ∵ ∠PQR = ∠PRQ (Given)