The value of 1ab + c1bc + a1ca +&

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 Multiple Choice QuestionsMultiple Choice Questions

481.

If A2 - A + I = 0, then matrix A-1 will be equal to

  • A + I

  • I - A

  • A

  • A - I


482.

For how many values of x in the interval [- 4, - 1] the matrix 3- 1 + x23- 1x + 2x + 3- 12 is singular ?

  • 2

  • 1

  • 0

  • 3


483.

If A = 101011100, then A is a

  • singular

  • non-singular

  • symmetric

  • unit matrix


484.

Let fx = sin3x12cos3x2 + sin3x22cos3x- 12cos23x2 -  sin23x2tan3x41 + 2tan3x. Then, the value of f'(x) at x = (2n + 1) π, n  I (the set of integers) is equal to

  • (- 1)n

  • (- 1)+ 1

  • 3

  • 9


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485.

The value of 1ab + c1bc+ a1ca +b is

  • 0

  • a + b + c

  • abc

  • 1


A.

0

Let  = 1ab + c1bc+ a1ca +bApplying C3  C3 + C2, we get = 1aa + b + c1ba + b + c1ca + b + c    = a + b +c1a11b11c1    = a + b +c × 0           C1 and C3 are identical    = 0


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486.

If 2x - 1274 = 320- 2, then the value of x will be

  • 2274 

  • 127/22

  • 227/21

  • None of the above


487.

If 02βγαβ- γα- βγ is orthagonal, then the values of α, β and  γ will be

  • α = ± 15, β = ± 13, γ = ± 12

  • α = ± 16, β = ± 17, γ = ± 13

  • α = ± 13, β = ± 13, γ = ± 13

  • α = ± 12, β = ± 16, γ = ± 13


488.

If A = - 22- 32, B = 0- 110, then (B-1A-1) is equal to

  • 2223

  • 3- 222

  • 1102223

  • 11032- 22


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489.

A square matrix [a0] in which a0 = 0 for i  j and a0 = k (constant) for i = j is callled a

  • unit matrix

  • scalar matrix

  • null matrix

  • diagonal matrix


490.

If A = 023- 4, hA = 03a2b24, then the values of h, a, b are respectively

  • - 6, - 12, - 18

  • - 6, 4, 9

  • - 6, - 4, - 9

  • - 6, + 12, 18


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