If a = 2, b = 3, then find the values of the following:
(i) (ab + ba)-1 (ii) (aa + bb)-1
Show that
(xa - b)a + b. (xb - c)b + c. (xc - a)c + a = 1
(xa - b)a + b. (xb - c)b + c. (xc - a)c + a
= x(a - b) (a + b). x(b - c) (b + c). x(c - a) (c + a)
= xa2 - b2. xb2 - c2. xc2 - a2
= xa2 - b2 b2 + b2 - c2 + c2 - a2
= X0
= 1