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Given polynomials are: p(x) = 2x 2 + 3x – 5 and q(x) = x 3 – 2x 2 + 4 Now, p(x) + q(x) = (2x 2 + 3x – 5) + (x 3 – 2x 2 + 4) = 2x 2 + 3x – 5 + x 3 – 2x 2 + 4 = x 3 + 3x – 1 Since, highest power on the variable is 3. Hence, degree of the polynomial is 3.

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Polynomials

Short Answer Type

361. Prove that x² + 6x + 15 has no zero.

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362. How many zeroes can, a polynomial of degree n have ?

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363.

The graph of the polynomial y = ax² + bx + c is shown in Fig. 2.2. Write the value of b² – 4ac.

y = ax²+ bx + c.

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364. Write the polynomial, the product and soon of whose heroes are

negative 9 over 2 space and space minus 3 over 2

respectively.

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365. What is the product of the zeroes of quadratic polynomial 3x² + 11x – 6 ?

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366. Find the number of zeroes of the function, whose graph is given below in Fig.

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367. Find a quadratic polynomial, the sum and product of whose zeroes are 1 and –2 respectively.

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368. Write the degree of the polynomial p(x) = x² – 2x +x³ +8.

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369. Graph of a linear polynomial is a straight line.
If points (1,–1), (2, 1),

open parentheses 3 over 2 comma 0 close parentheses

lie on this graph of polynomial. Write the zero of the polynomial.

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370. Write the degree of the polynomial obtained by adding the two polynomials
p(x)=2x² + 3x – 5 and q(x) = x³ – 2x² + 4.

Given polynomials are:
p(x) = 2x² + 3x – 5
and q(x) = x³ – 2x² + 4
Now,
p(x) + q(x) = (2x² + 3x – 5) + (x³ – 2x² + 4)
= 2x² + 3x – 5 + x³– 2x² + 4
= x³ + 3x – 1
Since, highest power on the variable is 3.
Hence, degree of the polynomial is 3.

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