If α and β are the zeroes of the quadratic polynomial P(x) = K

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(a)      straight alpha over straight beta plus straight beta over straight alpha             (b)   space space straight alpha squared plus straight beta squared

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427. If α and β are the zeroes of the quadratic polynomial P(x) = Kx2 + 4x + 4 such that α2 + β2 = 24, find the value of K.


Since, α and β are the zeroes of the quadratic polynomial P(x) Kx + 4x + 4, then

straight alpha plus straight beta equals fraction numerator negative straight b over denominator straight a end fraction equals fraction numerator negative 4 over denominator straight K end fraction space and space straight alpha comma space straight beta space equals space straight c over straight a equals 4 over straight K
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rightwards double arrow          space space space space left parenthesis straight alpha plus straight beta right parenthesis squared minus 2 αβ space equals space 24
rightwards double arrow        open parentheses fraction numerator negative 4 over denominator straight K end fraction close parentheses squared minus 2 open parentheses 4 over straight K close parentheses space equals space 24
rightwards double arrow           16 over straight K squared minus 8 over straight K equals 24
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rightwards double arrow              16 minus 8 straight K space equals space 24 space straight K squared
rightwards double arrow    24 space straight K squared plus 8 straight K minus 16 space equals 0
rightwards double arrow space space space 8 left parenthesis 3 straight K squared plus straight K minus 2 right parenthesis space equals space 0
space space space rightwards double arrow space space space space space space space space space space space space space space 3 straight K squared plus straight K minus 2 equals 0
rightwards double arrow        3 straight K squared plus 3 straight K minus 2 straight K plus 2
rightwards double arrow    3 straight K left parenthesis straight K plus 1 right parenthesis minus 2 left parenthesis straight K plus 1 right parenthesis space equals space 0
rightwards double arrow           space space space space left parenthesis 3 straight K minus 2 right parenthesis space left parenthesis straight K plus 1 right parenthesis space equals space 0
 rightwards double arrow       space 3 straight K minus 2 equals 0 space space or space space straight K plus 1 equals 0
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