If p = 2 - a, then prove that a3 + 6ap + p3 - 8 = 0. from Mat
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    Polynomials

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    160. If p = 2 - a, then prove that a3 + 6ap + p3 - 8 = 0.

    p = 2 - a
    ⇒    p + a - 2 = 0
    ∴ p3 + a3 + (- 2)3 = 3 (p) (a) (- 2)
    | Using Identity VI
    ⇒     p3 + a3 - 8 = - 6ap
    ⇒ a3 + 6ap +p3 - 8 = 0

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