Short Answer TypeA die thrown once. Find the probability of getting
(i) an even prime number
(ii) a multiple of 3
If a die thrown once then possible outcomes are
S = {1, 2, 3, 4, 5, 6} i.e. n(S) = 6
(i) Let A be the favourable outcomes of getting an even prime number, then
A = [2] i.e. n(A) = 2
Therefore, P(A) = 
(ii) Let B be the favourable outcomes of getting a multiple of three, then
B = {3,6} i.e. n(B) = 2
Therefore, P(B) = 
Switch
write 1 - P 
.
