Short Answer TypeA box has cards numbered 14 to 99. Cards are mixed throughly and a card is drawn from the bag at random. Find the probability that the number on the card drawn from the box is
(i) an odd number.
(ii) a perfect square number.
(iii) an number divisible by 7.
A card is drawn at random from a well -shuffled fled pack of 52 playing cards. Find the probability of getting neither a red card nor a queen.
Three different coins are tossed together. Find the probability of getting
(i) exactly two heads
(ii) at least two heads
(iii) at least two tails.
A number x is selected at random from the numbers 1, 2, 3, and 4. Another number y is selected at random from the numbers 1, 4, 9 and 16. Find the probability that product of x and y is less than 16.
The different dice are tossed together. Find the probability that the product of the two number on the top of the dice is 6.
Long Answer TypeShort Answer TypeA number is chosen at random from the number –3, –2, –1, 0, 1, 2, 3. What will be the probability that square of this number is less then or equal to 1?
Two different dice are thrown together. Find the probability that the numbers obtained
(i) have a sum less than 7
(ii) have a product less than 16
(iii) is a doublet of odd numbers.
The outcomes when two dice are thrown together are
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
Total number of outcomes = 36
(i) Let A be the event of getting the numbers whose sum is less than 7.
The outcomes in favour of event A are (1, 1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (4,1), (4,2) and (5,1).
Number of favourable outcomes = 15
(ii) Let B be the event of getting the numbers whose product is less than 16.
The outcomes in favour of event B are (1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (4,1), (4,2), (4,3), (5,1), (5,2), (5,3), (6,1) and (6,2).
Number of favourable outcomes = 25
iii) Let C be the event of getting the numbers which are doublets of odd numbers.
The outcomes in favour of event C are (1,1), (3,3) and (5,5).
Number of favourable outcomes = 3
Long Answer TypePeter throws two different dice together and finds the product of the two numbers obtained. Rina throws a die and squares the number obtained. Who has the better chance to get the number 25.
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