The coin has 1 marked on on face and 6 on the other. Let H = 1 or T = 6. The coin and die are tossed together.
S = {(H,1), (H,2), (H,3), (H,4), (H,5), (H,6), (T,1), (T,2), (T,3), (T,4), (T,5), (T,6)}
S = {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}
n(S) = 12
Event A: A total of 3 is obtained. A = {(1, 2)}
n(A) = 1
Hence,